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S_A_V [24]
4 years ago
5

Which expression is equivalent to 9(9m+3t)

Mathematics
2 answers:
vitfil [10]4 years ago
7 0

Answer:

81m + 27t

Step-by-step explanation:

LUCKY_DIMON [66]4 years ago
4 0

Answer:

your awnser is 81m + 27t

You might be interested in
Write an equation for the line in slope-intercept form​
quester [9]

Answer:

y = -3/1x + 2

Step-by-step explanation:

1. Find the slope

The points I will use are (-1,5) and (0,2), where x1 = -1, y1 = 5, x2 =0, and y2 =2.

y2-y1/x2-x1

2-5/0-(-1) = -3/1

2. Find the y-intercepy

y = mx + b

You can use any x or y point. I'll use (-1,5)

m= slope, which is -3/1

5= -3/1(-1) +b

5= 3 + b

Subtract 3 from 5 and 3 to get 2=b.

3. Rewrite in slope-intercept form

y = -3/1x + 2

4 0
4 years ago
How much times does 3 go into 46?
valkas [14]
46/3=15.3 so 3 goes into 46 about 13 times
4 0
3 years ago
3 8/9 + 1 5/12<br><br><br> Solve.
slavikrds [6]

Answer:

=5 11/36(Decimal: 5.305556)

Step-by-step explanation:

389+1512

=359+1512

=359+1712

=19136

=5 11/36

6 0
3 years ago
3 x a x 2 x b please tell me the answer if you know it
nevsk [136]

Answer:

6ab

Step-by-step explanation:

3 x a x 2 x b

= 3 x 2 x a x b      ( because multiplication is commutative, which basically means you can move the  numbers and variables anywhere in the expression).

= 6ab     ( we leave out the multiplication signs. They are understood.)

4 0
3 years ago
A Niffler is a magical creature who loves to collect shiny objects and store them in their pouch, much like a kangaroo. The amou
Fudgin [204]

Answer:

Probability that a Niffler can hold more than 32 pounds of shiny objects in their pouch is 0.1515.

Step-by-step explanation:

We are given that the amount a Niffler can hold in their pouch is approximately normally distributed with a mean of 25 pounds of shiny objects and a standard deviation of 6.8 pounds.

Let X = <u><em>amount a Niffler can hold in their pouch</em></u>

So, X ~ Normal(\mu=25,\sigma^{2} =6.8^{2})

The z score probability distribution for normal distribution is given by;

                                Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population mean = 25 pounds

            \sigma = standard deviation = 6.8 pounds

Now, the probability that a Niffler can hold more than 32 pounds of shiny objects in their pouch is given by = P(X > 32 pounds)

  P(X > 32 pounds) = P( \frac{X-\mu}{\sigma} > \frac{32-25}{6.8} ) = P(Z > 1.03) = 1 - P(Z \leq 1.03)

                                                             = 1 - 0.8485 = 0.1515

<em>The above probability is calculated by looking at the value of x = 1.03 in the z table which has an area of 0.8485.</em>

<em />

Hence, the probability that a Niffler can hold more than 32 pounds of shiny objects in their pouch is 0.1515.

4 0
3 years ago
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