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liq [111]
3 years ago
9

Larry has 62 nickels, 24 dimes, 17 quarters, and 11 fifty-cent pieces. How much money does he have?

Mathematics
2 answers:
Len [333]3 years ago
7 0

Answer:

Larry has 1525 cents or 15.25 dollars.

Step-by-step explanation:

The following are the values for each of the coins:

1 Nickel=5 cents

1 Dime = 10 cents

1 Quarter = 25 cents

1 Fifity-cent = 50 cents

So the total value of the Larry's have is

Total money = 62*5 cents + 24*10 cents + 17*25 cents + 11*50 cents

Total money = 310 cents + 240 cents + 425 cents + 550 cents

Total money = 1525 cents

This is equal to 15.25 dollars.

Viefleur [7K]3 years ago
3 0
C. $15.25 apex because its on apex
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Sam has $2.25 in quarters and dimes, and the total number of coins is 12. How many quarters and how many dimes?
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N₁*$0.10 + n₂*$0.25 = $2.25

n₁ + n₂ = 12

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This means that:

n₁ = 12 - n₂

And:

(12 - n₂)*$0.10 + n₂*$0.25 = $2.25

12*$0.10 - n₂*$0.10 + n₂*$0.25 = $2.25

$1.20 + n₂*$0.05*(5-2) = $2.25

$1.20 + n₂*$0.05*3 = $2.25

$1.20 + n₂*$0.15 = $2.25

n₂*$0.15 = $2.25 - $1.20

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n₂ = ($1.05)/($0.15)

n₂ = 7

If n₂ = 7:

n₁ + 7 = 12

Therefore, n₁ = 5.

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Answer:

5 dimes and 7 quarters.
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Josiah want to gp to the movies with his friends. Tickets are $8.50 plus he must play Fangalingo a $3 transaction fee for purcha
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Answer:

The equation that represents the number of tickets that Josiah can buy with $45.50

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Step-by-step explanation:

Let the number of tickets be represented by x

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