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3 years ago

C ÷ 3/4 = 4. whats c?

Mathematics

1 answer:

andrew11 [14]3 years ago

8 0

Answer:

Step-by-step explanation:

when a division crosse's an equal sin it becomes a multiplication

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Could someone pls explain me

Fiesta28 [93]

Hi! im in 7th and learning this, its 26x9 and then minus that by 9x9

5 0

3 years ago

For their twentieth wedding anniversary, Richard and Sylvia had a party for several of their best friends. Things were going alo

kompoz [17]

Answer:

Richard is older

Step-by-step explanation:

We can set up an inequality for both statements.

Let r equal Richard's age and s equal Sylvia's age.

"I am older than my wife."

Since Richard is speaking, the inequality would look like this:

r > s

This means Richard is older than Sylvia.

"I am younger than my husband."

Since Sylvia is speaking, the inequality would look like this:

s < r

This means that Sylvia is younger than Richard.

We can flip one inequality to "see" them from the same perspective.

Let's use s < r

To make it so that we can see the relationship from Richard's perspective, flip the entire inequality.

s < r

r > s

The inequality from the first quote is identical to this one!

Therefore, Richard is older than Sylvia.

8 0

3 years ago

How many 1/10's are in 2/5?

goblinko [34]

There is 4 1/10's in 2/5.

You do this by turning 2/5 into a fraction with a denominator of 10, so it will be 4/10. 1/10 + 1/10 + 1/10 + 1/10 = 4/10

3 0

4 years ago

Solve the system by using a matrix equation.<br> --4x - 5y = -5<br> -6x - 8y = -2

evablogger [386]

Answer:

Solution : (15, - 11)

Step-by-step explanation:

We want to solve this problem using a matrix, so it would be wise to apply Gaussian elimination. Doing so we can start by writing out the matrix of the coefficients, and the solutions ( - 5 and - 2 ) --- ( 1 )

$\begin{bmatrix}-4&-5&|&-5\\ -6&-8&|&-2\end{bmatrix}$

Now let's begin by canceling the leading coefficient in each row, reaching row echelon form, as we desire --- ( 2 )

Row Echelon Form :

$\begin{pmatrix}1\:&\:\cdots \:&\:b\:\\ 0\:&\ddots \:&\:\vdots \\ 0\:&\:0\:&\:1\end{pmatrix}$

Step # 1 : Swap the first and second matrix rows,

$\begin{pmatrix}-6&-8&-2\\ -4&-5&-5\end{pmatrix}$

Step # 2 : Cancel leading coefficient in row 2 through $R_2\:\leftarrow \:R_2-\frac{2}{3}\cdot \:R_1$ ,

$\begin{pmatrix}-6&-8&-2\\ 0&\frac{1}{3}&-\frac{11}{3}\end{pmatrix}$

Now we can continue canceling the leading coefficient in each row, and finally reach the following matrix.

$\begin{bmatrix}1&0&|&15\\ 0&1&|&-11\end{bmatrix}$

As you can see our solution is x = 15, y = - 11 or (15, - 11).

4 0

3 years ago

Help please<br><br>What is 2/3÷1/2

Luba_88 [7]

Answer: B

Step-by-step explanation:

2/3 x 2/1 =4/3

3 0

2 years ago