B) On one rectangular coordinate system, show approximate radian values for one circle, as
1 answer:
Answer:
(See explanation below for further details)
Step-by-step explanation:
Any point in rectangular form can be described in terms of radius and angle of the circle. That is:
Since circunference is divided into 8 equal parts, the point can be modelled as:
The approximate radian and degree values for one circle are:
Radians
Degrees
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For the first circle, let's use the pythagorean theorem
now, it just so happen that the hypotenuse on that triangle, is actually 17, but we used the pythagorean theorem to find it, and the pythagorean theorem only works for right-triangles.
so if the hypotenuse is actually 17, that means that triangle there is actually a right-triangle, meaning that the radius there, and the outside line there, are both meeting at a right-angle.
when an outside line touches the radius line, and they form a right-angle, the outside line is indeed a tangent line, since the point of tangency is always a right-angle with the radius.
now, let's check for second circle
well, low and behold, we didn't get our hypotenuse as 16 after all, meaning, that triangle is NOT a right-triangle, and that outside line is not touching the radius at a right-angle, therefore is NOT a tangent line.
let's check the third circle
this time, we did get our hypotenuse to 65, the triangle is a right-triangle, so the outside line is indeed a tangent line.
now, it just so happen that the hypotenuse on that triangle, is actually 17, but we used the pythagorean theorem to find it, and the pythagorean theorem only works for right-triangles.
so if the hypotenuse is actually 17, that means that triangle there is actually a right-triangle, meaning that the radius there, and the outside line there, are both meeting at a right-angle.
when an outside line touches the radius line, and they form a right-angle, the outside line is indeed a tangent line, since the point of tangency is always a right-angle with the radius.
now, let's check for second circle
well, low and behold, we didn't get our hypotenuse as 16 after all, meaning, that triangle is NOT a right-triangle, and that outside line is not touching the radius at a right-angle, therefore is NOT a tangent line.
let's check the third circle
this time, we did get our hypotenuse to 65, the triangle is a right-triangle, so the outside line is indeed a tangent line.
Answer:
Step-by-step explanation:
Given functions are:
We have to find:
(s.t)(x) => this means we have to multiply the two functions to get the result.
So,
Also we have to find
(s-t)(x) => we have to subtract function t from function s
Also we have to find,
(s+t)(-3) => first we have to find sum of both functions and then put -3 in place of x
Putting x = -3
Hence,