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harina [27]
3 years ago
12

B) On one rectangular coordinate system, show approximate radian values for one circle, as

Mathematics
1 answer:
sleet_krkn [62]3 years ago
8 0

Answer:

(See explanation below for further details)

Step-by-step explanation:

Any point in rectangular form can be described in terms of radius and angle of the circle. That is:

P = (r\cdot \cos \theta, r\cdot \sin \theta)

Since circunference is divided into 8 equal parts, the point can be modelled as:

P = (r\cdot \cos \frac{2\pi\cdot n}{8}, r \cdot \sin \frac{2\pi\cdot n}{8} )

The approximate radian and degree values for one circle are:

Radians

0 (0), \frac{\pi}{4} (0.785), \frac{\pi}{2} (1.571), \frac{3\pi}{4} (2.355), \pi (3.142), \frac{5\pi}{4} (3.925), \frac{3\pi}{2} (4.71), \frac{7\pi}{4} (5.495), 2\pi (6.280)

Degrees

0^{\circ}, 45^{\circ}, 90^{\circ}, 135^{\circ}, 180^{\circ}, 225^{\circ}, 270^{\circ}, 315^{\circ}, 360^{\circ}

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valina [46]

Answer:

P(Same)=\frac{61}{190}

Step-by-step explanation:

Given

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White = 6

Black = 9

Required

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The total number of ball is:

Total = 5 + 6 + 9

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This is calculated as:

P(Same)=P(Red\ and\ Red) + P(White\ and\ White) + P(Black\ and\ Black)

So, we have:

P(Same)=\frac{n(Red)}{Total} * \frac{n(Red) - 1}{Total - 1} + \frac{n(White)}{Total} * \frac{n(White) - 1}{Total - 1}  + \frac{n(Black)}{Total} * \frac{n(Black) - 1}{Total - 1}

<em>Note that: 1 is subtracted because it is a probability without replacement</em>

P(Same)=\frac{5}{20} * \frac{5 - 1}{20- 1} + \frac{6}{20} * \frac{6 - 1}{20- 1}  + \frac{9}{20} * \frac{9- 1}{20- 1}

P(Same)=\frac{5}{20} * \frac{4}{19} + \frac{6}{20} * \frac{5}{19}  + \frac{9}{20} * \frac{8}{19}

P(Same)=\frac{20}{380} + \frac{30}{380}  + \frac{72}{380}

P(Same)=\frac{20+30+72}{380}

P(Same)=\frac{122}{380}

P(Same)=\frac{61}{190}

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3 years ago
What is the GCF for each set of numbers 15 and 35. show ur work
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