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yarga [219]
2 years ago
13

❗❗❗❗HELP❗❗❗❗

Mathematics
2 answers:
den301095 [7]2 years ago
8 0

Answer:

The correct option is C: 15,040(1.21)t ≤ 100,000

Step-by-step explanation:

Consider the provided information.

It is given that after 7 a.m power usage on a college campus increases at a rate of 21% per hours.

Let t is the number of hours then the rate of increase will be:

21\%t=\frac{21}{100}t=0.21t

Prior to 7 a.m., 15,040 kWh have been used. Thus the increment of power use after t hours will be:

Increase=15,040(0.21)t

The total power consumption will be:

Previous power consumption + increase in power

15,040+15,040(0.21)t\\=15,040(1+0.21)t\\=15,040(1.21)t

The power usage on campus will be less than or equal to 100,000.

15,040(1.21)t\leq 100,000

Hence, the required inequality is 15,040(1.21)t\leq 100,000.

Thus, the correct option is C: 15,040(1.21)t ≤ 100,000

just olya [345]2 years ago
6 0

The power increases by 21% per hour. 21% written as a decimal is 0.21.

Because it increases you would multiply the starting value by 1.21 times the number of hours (t).

That needs to be less than or equal to 100,00

The equation would be:

C: 15,040(1.21)t ≤ 100,000

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Find the domain and range of the function f(x) = 5x – 41 + 3
Strike441 [17]

Answer: is it for math

Step-by-step explanation:

4 0
2 years ago
Solve for the variable a D =a+b-c/3
yuradex [85]
Hey there,
solving for a is just like you think of all other letter as a constant
i.e the only variable is a
so you need to subtract b as a start
      d=a+b-c/3
-b             -b
=============

    -b+d=a-c/3                now it's time to add c/3 (isolate a by itself in one side)

     -b+d=a-c/3
+c/3         +c/3
==============
c/3-b+d=a

Hence you have solved for a




4 0
3 years ago
Help me to answer this pls​
nlexa [21]

Problem 1

x = measure of angle N

2x = measure of angle M, twice as large as N

3(2x) = 6x = measure of angle O, three times as large as M

The three angles add to 180 which is true of any triangle.

M+N+O = 180

x+2x+6x = 180

9x = 180

x = 180/9

x = 20 is the measure of angle N

Use this x value to find that 2x = 2*20 = 40 and 6x = 6*20 = 120 to represent the measures of angles M and O in that order.

<h3>Answers:</h3>
  • Angle M = 40 degrees
  • Angle N = 20 degrees
  • Angle O =  120 degrees

====================================================

Problem 2

n = number of sides

S = sum of the interior angles of a polygon with n sides

S = 180(n-2)

2700 = 180(n-2)

n-2 = 2700/180

n-2 = 15

n = 15+2

n = 17

<h3>Answer: 17 sides</h3>

====================================================

Problem 3

x = smaller acute angle

3x = larger acute angle, three times as large

For any right triangle, the two acute angles always add to 90.

x+3x = 90

4x = 90

x = 90/4

x = 22.5

This leads to 3x = 3*22.5 = 67.5

<h3>Answers:</h3>
  • Smaller acute angle = 22.5 degrees
  • Larger acute angle = 67.5 degrees
4 0
2 years ago
1. Find the domain and range of the relation and determine whether it is a function.
Katyanochek1 [597]
A. the relation is a function
8 0
3 years ago
Daily low temperatures in Columbus, OH in January 2014 were approximately normally distributed with a mean of 15.45 and a standa
Alona [7]

Answer: 12.10

Step-by-step explanation:

Given : Mean : \mu = 15.45

Standard deviation : \sigma = 13.70

The formula to calculate the z-score :-

z=\dfrac{x-\mu}{\sigma}

For x= 5 degrees

z=\dfrac{5-15.45}{13.70}=-0.7627737226\approx-0.76

For x= 10 degrees

z=\dfrac{10-15.45}{13.70}=-0.397810218\approx-0.40

The P-value : P(-0.76

=0.3445783-0.2236273=0.120951\approx0.1210

In percent , 0.1210\times100=12.10\%

Hence, the percentage of days had a low temperature between 5 degrees and 10 degrees = 12.10%

5 0
2 years ago
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