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densk [106]
3 years ago
15

ASAP

Mathematics
1 answer:
Ulleksa [173]3 years ago
8 0

Answer:

C. (7, –3)

Step-by-step explanation:

5x+6y=17

-10x-9y=-43

Multiply the first equation by 2

2(5x+6y)=17*2

10x +12y = 34

Add this equation to the second equation to eliminate x

-10x-9y=-43

10x +12y = 34

---------------------

   3y = -9

Divide by 3

3y/3 = -9/3

y = -3

Now we need to find x

5x+6y = 17

5x +6(-3) = 17

5x-18 = 17

Add 18 to each side

5x-18+18 =17+18

5x =35

Divide by 5

5x/5 = 35/5

x =7

(7,-3)

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I need help with this question. can someone please help me
Ahat [919]
-2x + y =3
use 5 number and put it in above equation to find y, I will use -2,-1,0,1,2
x      y
-2   -1
-1    1
 0    3
 1    5
 2    7

Then draw the graph, find another point in the graph which intersect the slope, 
lets say i found (-3,-3)which is on the slope
to prove it, i put (-3,-3) in the equation -2x + y = 3
and i got 
3 = 3
Thus it is correct.

7 0
3 years ago
Find the value of x in 18 : 9 = 36 : x?
Misha Larkins [42]

Answer is B Step-by-step explanation:

18/9/ 36

36/ 2

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8 0
3 years ago
How much will you get when you split 650 dollars
oksano4ka [1.4K]

Answer:do u mean divided 2?, then the answer is 325

Step-by-step explanation:650/2

5 0
3 years ago
Read 2 more answers
Identify the constant term in the function. y=−x2+3x−4
Oduvanchick [21]

constant term in any function is the term whose value does not change on variation of other parameters or in other case. We can also say constant term is independent of variable parameters.

take example

y = x + 3

here 3 is constant term which will not change either I change x or y . 3 is independent . it's just helps equation to hold information that overall in equation its matter.

so in given problem -4 is the constant

3 0
3 years ago
In AABC, m A= 60°, m_C = 30°, and AB = 6 inches. What is the length of side BC?
nlexa [21]

Answer:

answer is (C)

Step-by-step explanation:

this is a right angle triangle

so tan 60 degree = bc/6

√3. = bc/6

√3×6= bc

10.39 inches

8 0
2 years ago
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