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pogonyaev
3 years ago
13

What are the roots of the quadratic equation x2+2x=-5

Mathematics
1 answer:
stiks02 [169]3 years ago
5 0

Answer:

x = -1 +/-2i

Step-by-step explanation:

Write the equation in standard form to find the roots, also known as the solutions, zeros, or x-intercepts, of the quadratic.

x² + 2x + 5 = 0

Use the quadratic formula by substituting a= 1, b = 2 and c = 5.

x = \frac{-2 +/- \sqrt{(-2)^2 - 4(1)(5)} }{2(1)} = \frac{-2 +/-\sqrt{4 -20 } }{2} = \frac{-2 +/-\sqrt{-16 } }{2} = \frac{-2 +/-4i }{2} = -1 +/-2i

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Find the two Z-scores that separate the middle 73.72% on the Standard Normal Curve.
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Answer:

+1.12 and -1.12

Step-by-step explanation:

Let the two z scores be -z_1and+z_1.

Since  the two Z-scores that separate the middle 73.72% on the Standard Normal Curve, this can be represented by the equation:

P(-z_1

From the z table of the normal distribution, z₁ = 1.12. That is a z score of 1.12 gives 0.8686.

The two z scores are +1.12 and -1.12 = ± 1.12

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8(8p+8)=640 solve <br> Answer ASAP please
Ede4ka [16]

Answer:

p = 9

Step-by-step explanation:

8(8p + 8) = 640

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6 0
3 years ago
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After 8 points are added to each score in a sample, the mean is found to be M= 40. What was the value for the original mean
MArishka [77]

Answer:

The value for the original mean = 32

Step-by-step explanation:

Here, we want to calculate the original value of the mean.

Let the number of samples be n

Mathematically;

mean = Total value/n

Now, we added 8 to each of values; total value added = 8 * n = 8n

Now, for the new mean of 40; we have

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kindly recall from the beginning of the solution;

mean = Total value/n

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