Answer:
19.4 cubic meter
Step-by-step explanation
Round your answer to the nearest tenth of a cubic centimeter.
Answer:
x=5
Step-by-step explanation:
2(x+4)+2x+3=3x+16
One solution was found :
x = 5
Answer:
Gerrard
Step-by-step explanation:
Let the size of each poster be ![x](https://tex.z-dn.net/?f=x)
Eve's poster portion painted will be
![=\frac{1}{6}\times x\\=\frac{x}6}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B6%7D%5Ctimes%20x%5C%5C%3D%5Cfrac%7Bx%7D6%7D)
Gerrard's painted portion will be:
![=\frac{1}{5}\times x\\=\frac{x}{5}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B5%7D%5Ctimes%20x%5C%5C%3D%5Cfrac%7Bx%7D%7B5%7D)
From the two inequalities, we find that
is greater than
by x/30
![\frac{x}{5}-\frac{x}{6}\\=\frac{x}{30}\\](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B5%7D-%5Cfrac%7Bx%7D%7B6%7D%5C%5C%3D%5Cfrac%7Bx%7D%7B30%7D%5C%5C)
hence Gerrard has the larger blue section. His portion is 16.67% greater than Eve's
Answer:
the total area is 15.6 square units
Step-by-step explanation:
hello,
you can find the total area dividing the shape into two known shapes
total area= area of the trapezoid +area of the semicircle
then
step one
find the area of the isosceles trapezoid using
![A=\frac{a+b}{2}*h](https://tex.z-dn.net/?f=A%3D%5Cfrac%7Ba%2Bb%7D%7B2%7D%2Ah)
where
a is the smaller base
b is the bigger base
h is theheight
A is the area
let
a=2
b=5
h=4
put the values into the equation
![A=\frac{a+b}{2}*h\\A=\frac{5+2}{2}*4\\A=3.5*4\\A=14](https://tex.z-dn.net/?f=A%3D%5Cfrac%7Ba%2Bb%7D%7B2%7D%2Ah%5C%5CA%3D%5Cfrac%7B5%2B2%7D%7B2%7D%2A4%5C%5CA%3D3.5%2A4%5C%5CA%3D14)
Step two
find the area of the semicircle
the area of a circle is given by
![A_{c}=\pi \frac{d^{2}}{4}\\](https://tex.z-dn.net/?f=A_%7Bc%7D%3D%5Cpi%20%20%5Cfrac%7Bd%5E%7B2%7D%7D%7B4%7D%5C%5C)
but, we need the area of half circle, we need divide this by 2
![A_{semic}=\frac{ \pi \frac{d^{2}}{4}}{2}\\A_{semic}= \pi \frac{d^{2}}{8}](https://tex.z-dn.net/?f=A_%7Bsemic%7D%3D%5Cfrac%7B%20%5Cpi%20%5Cfrac%7Bd%5E%7B2%7D%7D%7B4%7D%7D%7B2%7D%5C%5CA_%7Bsemic%7D%3D%20%5Cpi%20%5Cfrac%7Bd%5E%7B2%7D%7D%7B8%7D)
now the diameter of the semicircle is 2, put this value into the equation
![A_{semic}= \pi \frac{2^{2}}{8}\\\\A_{semic}= \pi \frac{1}{2}\\ A_{semic}=\frac{\pi }{2}\\](https://tex.z-dn.net/?f=A_%7Bsemic%7D%3D%20%5Cpi%20%5Cfrac%7B2%5E%7B2%7D%7D%7B8%7D%5C%5C%5C%5CA_%7Bsemic%7D%3D%20%5Cpi%20%5Cfrac%7B1%7D%7B2%7D%5C%5C%20A_%7Bsemic%7D%3D%5Cfrac%7B%5Cpi%20%7D%7B2%7D%5C%5C)
find the total area
total area= area of the trapezoid +area of the semicircle
![total\ area= 14+\frac{\pi }{2} \\total\ area=15.6](https://tex.z-dn.net/?f=total%5C%20area%3D%2014%2B%5Cfrac%7B%5Cpi%20%7D%7B2%7D%20%5C%5Ctotal%5C%20area%3D15.6)
so, the total area is 15.6 square units
Have a good day.