USE THE SQUARE ROOT PROPERTY!!!!!

Mathematics

2 answers:

nadya68 [22]2 years ago

6 0

Answer:

In area of a square we will learn how to find the area by counting squares.

To find the area of a region of a closed plane figure, we draw the figure on a centimeter squared paper and then count the number of squares enclosed by the figure.

We know, that square is a rectangle whose length and breadth are equal. In a square all four sides are equal.

Step-by-step explanation:

GaryK [48]2 years ago

3 0

Answer:

Step-by-step explanation:

x = original length of one side

(x-2)² = 20 inches²

x-2 = ±√20 = ±2√5

x = 2±2√5

2-2√5 is an extraneous solution,

so x = 2±2√5 ≈ 6.47 inches

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Find the value of sin(a/2) if cosa= 12/13<br>

daser333 [38]

Answer: sin $\frac{a}{2}$ = ± $\frac{1}{\sqrt{26} }$

Step-by-step explanation:

We very well know that,

cos2A=1−2sin²A

⟹ sinA = ± $\sqrt{(1-} \frac{cos2A}{2} )$

As required, set A = $\frac{a}{2}$ & cos a= $\frac{12}{13}$ ,thus we get

sin $\frac{a}{2}$ =± $\sqrt{\frac{1-cos a}{2} }$

∴ sin $\frac{a}{2}$ =± $\sqrt{\frac{1-\frac{12}{13} }{2} }$ = ± $\frac{1}{\sqrt{26} }$

since ,360° < $\frac{a}{2}$ <450°

,180° < $\frac{a}{2}$ <225°

Now, we are to select the value with the correct sign. It's is obvious from the above constraints that the angle a/2 lies in the III-quadrant where 'sine' has negative value, thus the required value is negative.

hope it helped!

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2 years ago

Dylan has a roll of wrapping paper that is5 meters long. How many centimeters of wrapping paper does he have.

In-s [12.5K]

500 centimeters I think *sweats nervously*

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2 years ago

2- ( - 4 ) + 3 (- 6 ) -2 =

Drupady [299]

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