Answer:
To subtract a number from another number, the sign of the number (which is to be subtracted) should be changed and then this number with the changed sign, should be added to the first number
Step-by-step explanation:
(i) Evaluate (+6) – (+2)
= (+6) + (-2) (charging the sign of the number to be subtracted and then adding)
On subtracting smaller number 2 from bigger number 6; we get 6 – 2 = 4
Since, the sign of bigger number is + (positive)
= +4 or 4
Therefore, (+6) – (+2) = 4
(ii) Evaluate (+5) – (-3)
= (+5) + (+3) (charging the sign of the number to be subtracted and then adding)
We know, to add a positive (+ ve) number to a positive (+ ve) number, the numbers should be added and positive sign should be attached to the sum obtained.
= +8
Therefore, (+5) – (-3) = 8
Answer:
The 10th term of the sequence is 200.
Step-by-step explanation:
Given that,
The sequence is as follows :
f(n)=100+10n
We need to find 10th term of the sequence.
Put n = 10 in the given expression.
f(10)=100+10(10)
= 100 + 100
= 200
Hence, the 10th term of the sequence is 200.
Answer:
7. 80 miles
8. F
Step-by-step explanation:
7. Jorge leaves 2 hours early, and is going 20 miles per hour. So before Marcos starts going, Jorge has gone 40 miles (2*20). Then, 1 hour later, Jorge is at 60 miles and Marcos is at 40 (because he goes 40 miles per hour in his car). Another hour later, Jorge is at 80 (60+20) and Marcos is at 80 as well (40 + 40). They will both have gone 80 miles when Marcus catches up.
8. You want to get <em>a</em> isolated.
A = h/2(a + b)
First, multiply both sides of the equation by the reciprocal of h/2.
2A/h = a + b
Then, subtract b from both sides.
2A-b/h = a
Answer:
First one is d and second one is c
Step-by-step explanation:
(6x+7)(x-8)
(6x)(x) = 6x^2
(6x)(-8) = -48
(7)(x) = 7x
(7)(-8) = -56
Add all like terms together and you get choice d.
(w+3)(w-3)
(w)(w) = w^2
(w)(-3) = -3w
(3)(w) = 3w
(3)(-3) = -9
Add all like terms together and you get choice c
<span>
0.009 is 1/10th of 0.09 which also mean that 0.09 is 10 times as big as 0.009
</span>