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3 years ago

Explain the relationship between the slope and the derivative of f(x) at xequals=a

Mathematics

1 answer:

Makovka662 [10]3 years ago

5 0

I am not sure but i think the slope is a line on a graph like posative negetive zero and undifined.

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11p + 2(p + 3) and 1 + p(13) + 2

Zarrin [17]

Answer:
1) 13p+6
2) 13p+3

6 0

3 years ago

Consider the function f ( x ) = − 2 x 3 + 27 x 2 − 108 x + 9 . For this function there are three important open intervals: ( − [

Darya [45]

Answer:

A=3 and B=6

Step-by-step explanation:

Increasing and Decreasing Intervals of Functions

Given f(x) as a real function and f'(x) its first derivative.

If f'(a)>0 the function is increasing in x=a

If f'(a)<0 the function is decreasing in x=a

If f'(a)=0 the function has a critical point in x=a

As we can see, the critical points may define open intervals where the function has different behaviors.

We have

$f ( x ) = - 2 x^3 + 27 x^2 - 108 x + 9$

Computing the first derivative:

$f' ( x ) = - 6 x^3 + 54 x - 108$

We find the critical points equating f'(x) to zero

$- 6 x^3 + 54 x - 108=0$

Simplifying by -6

$x^2 -9 x +18=0$

We get the critical points

$x=3,\ x=6$

They define the following intervals

$(-\infty,3),\ (3,6),\ (6,+\infty)$

Thus A=3 and B=6

3 0

3 years ago

Imagine the graph for the relation 4x-5y+20 = 0. What would be its slope?

muminat

4x - 5y + 20 = 0
 - 20 - 20
 4x - 5y = -20
4x - 4x - 5y = -20 - 4x
 -5y = -20 - 4x
 -5y = -4x - 20
 -5 -5
 y = ⁴/₅x + 4
The slope would be ⁴/₅.

4 0

3 years ago

Look at the figure what is the value of y √2y+3=11

Natasha_Volkova [10]

Answer:

y=2

Step-by-step explanation:

first solve those in the brackets then find the square root

2y+3=11

put like terms together

3 goes to the right side

2y=11-3

2=8

y=4

√4=2

y=2

3 0

3 years ago

39. Why are -2a and 18a like terms?

Vesnalui [34]

Answer:

they each share the same variable which is raised to the same exponent, 1

Step-by-step explanation:

7 0

2 years ago