Question

If p(x) = 5(x^2+1)+16 what is the value of p(11)

Answer 1

Answer:

p(11) = 626.

Step-by-step explanation:

Given  : p(x) = 5(x²+1)+16.

To find :  what is the value of p(11).

Solution : We have given  p(x) = 5(x²+1)+16.

For x = 11.

p(11) = 5((11)²+1)+16.

p(11) = 5 ( 121 + 1 ) +16.

p(11) = 5 (122) + 16.

p(11) =  610 + 16.

p(11) = 626.

Therefore,  p(11) = 626.

Answer 2

5(11^2+1)+16

5(121+1)+16

5(122)+16

610+16

p(11)=626