Given g(x)=-x-2g find g(-3)

100 points for correct answer

Tems11 [23]

Answer:

$\dfrac{x}{3}+\dfrac{3}{y}$

Step-by-step explanation:

Given fraction:

$\dfrac{xy+9}{3y}$

$\textsf{Apply the fraction rule} \quad \dfrac{a+b}{c}=\dfrac{a}{c}+\dfrac{b}{c}:$

$\implies \dfrac{xy}{3y}+\dfrac{9}{3y}$

Rewrite 9 as 3 · 3:

$\implies \dfrac{xy}{3y}+\dfrac{3 \cdot 3}{3y}$

Cancel the common factor y in the first fraction and the common factor 3 in the second fraction:

$\implies \dfrac{x\diagup\!\!\!\!y}{3\diagup\!\!\!\!y}+\dfrac{\diagup\!\!\!\!3 \cdot 3}{\diagup\!\!\!\!3y}$

$\implies \dfrac{x}{3}+\dfrac{3}{y}$

7 0

1 year ago

Tan(x+pi/2)= negative cot x

DIA [1.3K]

I'm only going to alter the left hand side. The right side will stay the same the entire time

I'll use the identity tan(x) = sin(x)/cos(x) and cot(x) = cos(x)/sin(x)
I'll also use sin(x+y) = sin(x)cos(y)+cos(x)sin(y) and cos(x+y) = cos(x)cos(y)-sin(x)sin(y)

So with that in mind, this is how the steps would look:

tan(x+pi/2) = -cot x
sin(x+pi/2)/cos(x+pi/2) = -cot x
(sin(x)cos(pi/2)+cos(x)sin(pi/2))/(cos(x)cos(pi/2)-sin(x)sin(pi/2)) = -cot x
(sin(x)*0+cos(x)*1)/(cos(x)*0-sin(x)*1) = -cot x
(0+cos(x))/(-sin(x)-0) = -cot x
(cos(x))/(-sin(x)) = -cot x
-cot x = -cot x

Identity is confirmed

6 0

4 years ago

Help me please!!!!!!!?

vovikov84 [41]

It is c.it is actually 1.548 but you round it so....

5 0

4 years ago

Read 2 more answers

Which geometric figure contains exactly two perpendicular lines

Leviafan [203]

Answer:

Like a square, a rectangle has lines that are perpendicular to two other lines. This means it also has four right angles.

Step-by-step explanation:

4 0

3 years ago

5. The recursive algorithm given below can be used to compute gcd(a, b) where a and b are non-negative integer, not both zero.

s2008m [1.1K]

Implementating the given algorithm in python 3, the greatest common divisors of (124 and 244) and (4424 and 2111) are 4 and 1 respectively.

The program implementation is given below and the output of the sample run is attached.

def gcd(a, b):

#initialize a function named gcd which takes in two parameters

if a>b:

#checks if a is greater than b

return gcd (b, a)

#if true interchange the Parameters and Recall the function

elif a == 0:

return b

elif a == 1:

return 1

elif((a%2 == 0)and(b%2==0)):

#even numbers leave no remainder when divided by 2, checks if a and b are even

return 2 * gcd(a/2, b/2)

elif((a%2 !=0) and (b%2==0)):

#checks if a is odd and B is even

return gcd(a, b/2)

else :

return gcd(a, b-a)

#since it's a recursive function, it recalls the function with new parameters until a certain condition is satisfied

print(gcd(124, 244))

print()

#leaves a space after the first output

print(gcd(4424, 2111))

Learn more :brainly.com/question/25506437

6 0

3 years ago