Step-by-step explanation:
From Trig
1 + tan²x = Sec²x
Also
Sec²x = 1/cos²x
Now
Cot²x = 1/tan²x = cos²x/sin²x
Putting all together
Cot²x(1+tan²x)
= Cot²x(sec²x)
= cos²x/sin²x(1/cos²x)
cos²x on the numerator and that one the denominator cancels out
we have
= 1/sin²x
From Trig
1/sin²x = cosec²x
So Our Answer = cosec²x.
Radar, I believe. Hope it helps! :)
Answer:
Step-by-step explanation:
I honestly don't know
This equatuon illustrates <span>distributive of multiplicatiton over addition.
</span><span>
If we have a set E with two relation * and + : (E,+,*)
we say that the relation * is distributive with respect to the relation
If a*(b+c) = a*b + a*c for every a,b,c from E</span>