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sveta [45]
3 years ago
14

-29/35 + 17/25 give your answer as a reduced fraction

Mathematics
1 answer:
Murrr4er [49]3 years ago
4 0
The answer to this is -26/175
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Ramp 10 feet high and 32 long
madam [21]

A. IMA = 32/10 = 3.2

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3 years ago
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Jeff uses 3 fifth-size strips to mode 3/5. He wants to use tenth-size strips to model an equivalent fraction. How many tenth-siz
galben [10]
Wouldn't it just be 6 tenth sized for 6/10
4 0
3 years ago
M is the incenter of triangle ABC. Find the lengths of MD and DC. (Look at pic)
Deffense [45]

Answer:

Part 1) MD=9\ units

Part 2) DC=12\ units

Step-by-step explanation:

Step 1

Find the length of MD

we know that

The incenter is the intersection of the angle bisectors of the three vertices of the triangle. Is the point forming the origin of a circle inscribed inside the triangle

so

In this problem

MD=ME=MF ------> is the radius of a circle inscribed inside the triangle

we have that

MF=9\ units

therefore

ME=9\ units

MD=9\ units

Step 2

Find the length of DC

we know that

In the right triangle MDC

Applying the Pythagoras theorem

MC^{2} =MD^{2}+DC^{2}

we have

MD=9\ units

MC=15\ units

substitute

15^{2} =9^{2}+DC^{2}

DC^{2}=225-81

DC=\sqrt{144}\ units

DC=12\ units

6 0
3 years ago
What’s the missing leg length
kow [346]

Answer:

15

Step-by-step explanation:

pythag theorum

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3 years ago
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Find the volume of the region bounded above by the elliptical paraboloid zequals=9 minus 4 x squared minus 5 y squared9−4x2−5y2
Virty [35]

Answer:

\int\limits^1_0 \int^1_0{z} \, dA

Step-by-step explanation:

\int\limits^1_0\int^1_0 {9-4x^2-5y^2dy} \, dx

\int\limits^1_0 {9y-4x^2y-\frac{5y^3}{3}|_0 ^1 } \, dx

\int\limits^1_0 {22/3 -4x^2} \, dx

You finish the leftover.

7 0
3 years ago
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