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scoray [572]
3 years ago
8

Oops I meant: what is -7 + 9 = x +1

Mathematics
2 answers:
iVinArrow [24]3 years ago
8 0

Answer:

x=1

Step-by-step explanation:

-7+9=x+1

2=x+1

2-1=x+1-1

1=x

Ivanshal [37]3 years ago
7 0

Hello!

-7 + 9 = x + 1

2 = x + 1

2 - 1 = x

1 = x

I hope this helps you! Have a lovely day!

- Mal

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Which of these quadratic expressions is equivalent to
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Answer:

B. (x+8)(x+4)

Step-by-step explanation:

{x}^{2}  + 12x + 32 \\  =  {x}^{2} + 8x + 4x + 32 \\  = x(x + 8) + 4(x + 8) \\  \red { \bold{ = (x + 8)(x + 4) }}

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What property is 11 multiplied by 12 = (10+1) multiplied by (10+2)
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So first you would divide 1950/6 to find the amount for one year of their age.
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3 years ago
Calc help pretty please
Gre4nikov [31]

Answer:

A.  77.4

Step-by-step explanation:

<u>Linear approximation formula</u>

L(x)=f(a)+f'(a)(x-a)

Given function:

f(x)=(x+1)^2

\boxed{\begin{minipage}{5.4 cm}\underline{Chain Rule for Differentiation}\\\\If  $y=f(u)$  and  $u=g(x)$  then:\\\\$\dfrac{\text{d}y}{\text{d}x}=\dfrac{\text{d}y}{\text{d}u}\times \dfrac{\text{d}u}{\text{d}x}$\\\end{minipage}}

\boxed{\begin{minipage}{5 cm}\underline{Differentiating $x^n$}\\\\If  $y=x^n$, then $\dfrac{\text{d}y}{\text{d}x}=xn^{n-1}$\\\end{minipage}}

\boxed{\begin{minipage}{4 cm}\underline{Differentiating $ax$}\\\\If  $y=ax$, then $\dfrac{\text{d}y}{\text{d}x}=a$\\\end{minipage}}

Use the chain rule to differentiate the function.

\textsf{Let }\:y=u^2\:\textsf{ where }u=(x+1)

Differentiate the two parts separately:

  y=u^2 \implies \dfrac{\text{d}y}{\text{d}u}=2u

  u=x+1 \implies \dfrac{\text{d}u}{\text{d}x}=1

Put everything back into the chain rule formula:

\begin{aligned} \implies \dfrac{\text{d}y}{\text{d}x} & =2u \times 1\\ & = 2u \\ & = 2(x+1)\\ & = 2x+2 \end{aligned}

\textsf{Therefore, }\:f'(x)=2x+2..

The <u>linear approximation</u> at a = 8 is:

\begin{aligned}L(x) & =f(a)+f'(a)(x-a)\\\\\implies L(x) & = f(8)+f'(8)(x-8)\\& = (8+1)^2+(2(8)+2)(x-8)\\& = 81+18(x-8)\\& = 18x-63\end{aligned}

Finally, substitute x = 7.8 into the <u>linear approximation equation</u>:

\begin{aligned}\implies L(7.8) & =18(7.8)-63\\& = 140.4-63\\& = 77.4\end{aligned}

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