A triangle has side lengths 3.4 cm, 4 cm, and 5.2 cm. The angle measures are 40°, 50°, and 90°.

Mathematics

2 answers:

ycow [4]2 years ago

8 0

Answer:

A triangle has side lengths 3.4 cm, 4 cm, and 5.2 cm. The angle measures are 40°, 50°, and 90°.

What type of triangle is this triangle?

acute scalene

right isosceles

acute isosceles

right scalene

Step-by-step explanation:

igomit [66]2 years ago

7 0

Answer:

Right scalene

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Please answer this question

Bogdan [553]

C=(1/4)*circumference
Area=pq+3.142r^2
60*3.142=pq+3.142p^2
q=((1/4)*2p*3.142)+2*3.142
q=1.571p+6.284
188.52=1.571p^2+6.284p+3.142p^2
188.52=4.713p^2+6.284p
188520=4713p^2+6284p

3 0

3 years ago

HELP?!? idk what im doing and nobody has asked this. will give brainliest answrr or whatever its called.

Illusion [34]

9514 1404 393

Answer:

$\textbf{A. }x=\dfrac{-4\pm2\sqrt{13}}{3}$

Step-by-step explanation:

First of all, subtract 12 from both sides of the equation to put it into standard form:

3x² +8x -12 = 0

Then identify the a, b, c of this form:

ax² +bx +c = 0

You see that a=3, b=8, c=-12.

Now use those values in the quadratic formula for the solutions:

$x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x=\dfrac{-8\pm\sqrt{8^2-4(3)(-12)}}{2(3)}\\\\x=\dfrac{-8\pm\sqrt{208}}{6}=\dfrac{-8\pm4\sqrt{13}}{6}\\\\\boxed{x=\dfrac{-4\pm2\sqrt{13}}{3}}\qquad\text{factor 2 from numerator and denominator}$