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SVEN [57.7K]
4 years ago
9

∆ABC rotates around point D to create ∆A'B'C'. However, only is shown. Based on the position of , what are the coordinates of A'

?
Mathematics
2 answers:
earnstyle [38]4 years ago
3 0
Well if you are talking to me about the following graphic <span>http://contentlaunch.ple.platoweb.com/testimagedb/53/5377183edb46ae5c5177efb0f9dfbbd1 then we have to say that it would be 4,1. Right there you can find A. Hope this has helped you</span>
HACTEHA [7]4 years ago
3 0

Answer:

(4, 1)

Step-by-step explanation:

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Plz help me i need this answe right now​
slamgirl [31]

Answer:

do u need the perimeter

3 0
4 years ago
Read 2 more answers
Write the product as a sum: 14cos(39x)sin(19x)
charle [14.2K]

Recall that

sin(<em>a</em> + <em>b</em>) = sin(<em>a</em>) cos(<em>b</em>) + cos(<em>a</em>) sin(<em>b</em>)

sin(<em>a</em> - <em>b</em>) = sin(<em>a</em>) cos(<em>b</em>) - cos(<em>a</em>) sin(<em>b</em>)

Adding these together gives

sin(<em>a</em> + <em>b</em>) + sin(<em>a</em> - <em>b</em>) = 2 sin(<em>a</em>) cos(<em>b</em>)

To get 14 cos(39<em>x</em>) sin(19<em>x</em>) on the right side, multiply both sides by 7 and replace <em>a</em> = 19<em>x</em> and <em>b</em> = 39<em>x</em> :

7 (sin(19<em>x</em> + 39<em>x</em>) + sin(19<em>x</em> - 39<em>x</em>)) = 14 cos(39<em>x</em>) sin(19<em>x</em>)

7 (sin(58<em>x</em>) + sin(-20<em>x</em>)) = 14 cos(39<em>x</em>) sin(19<em>x</em>)

7 (sin(58<em>x</em>) - sin(20<em>x</em>)) = 14 cos(39<em>x</em>) sin(19<em>x</em>)

4 0
3 years ago
PLSS IF YOU TRULY KNOW THIS HELP ME THANK YOU
Hitman42 [59]

Answer:

3,150

Step-by-step explanation:

600 x 5= 3000

600 ÷ 24= 25

25 x 6= 150

Add 3000 + 150= 3150

6 0
3 years ago
Read 2 more answers
Solve the system of equations algebraically.
Sveta_85 [38]

Answer:

x = -7 , y = 5 thus D)

Step-by-step explanation:

Solve the following system:

{4 x - 4 y = -48 | (equation 1)

5 x - 6 y = -65 | (equation 2)

Swap equation 1 with equation 2:

{5 x - 6 y = -65 | (equation 1)

4 x - 4 y = -48 | (equation 2)

Subtract 4/5 × (equation 1) from equation 2:

{5 x - 6 y = -65 | (equation 1)

0 x+(4 y)/5 = 4 | (equation 2)

Multiply equation 2 by 5/4:

{5 x - 6 y = -65 | (equation 1)

0 x+y = 5 | (equation 2)

Add 6 × (equation 2) to equation 1:

{5 x+0 y = -35 | (equation 1)

0 x+y = 5 | (equation 2)

Divide equation 1 by 5:

{x+0 y = -7 | (equation 1)

0 x+y = 5 | (equation 2)

Collect results:

Answer:  {x = -7 , y = 5

7 0
3 years ago
Given f(x) = 3x - 1 and g(x)= -x + 6, find f(-2) + g(5).<br><br> A.-6<br> B.6<br> C.8
vladimir2022 [97]
Find what f(x) is when x = -2
3(-2) - 1 = -7
Find g(x) when x = 5
-(5) + 6 = 1
Add -7 + 1
-7 + 1 = -6
Option A)
3 0
3 years ago
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