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SVEN [57.7K]
3 years ago
9

∆ABC rotates around point D to create ∆A'B'C'. However, only is shown. Based on the position of , what are the coordinates of A'

?
Mathematics
2 answers:
earnstyle [38]3 years ago
3 0
Well if you are talking to me about the following graphic <span>http://contentlaunch.ple.platoweb.com/testimagedb/53/5377183edb46ae5c5177efb0f9dfbbd1 then we have to say that it would be 4,1. Right there you can find A. Hope this has helped you</span>
HACTEHA [7]3 years ago
3 0

Answer:

(4, 1)

Step-by-step explanation:

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Question

The y-intercept of the function f(x) = x2+3x+2

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boyakko [2]

Answer:

(x,y) =(-4,-3) --- Vertex

x = -4 --- Axis of symmetry

Step-by-step explanation:

Given

y = -6(x + 4)^2 - 3

Solving (a): The vertex

For an equation written in

y = a(x - h)^2 + k

The vertex is:

(x,y) = (h,k)

By comparison:

y = a(x - h)^2 + k  and y = -6(x + 4)^2 - 3

-h =4       k = -3

h =-4         k = -3  

So, the vertex is:

(x,y) =(-4,-3)

Solving (b): The axis of symmetry

For an equation written in

y = a(x - h)^2 + k

The axis of symmetry is:

x = h

In (a):

h =-4

So:

x = -4

5 0
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Answer:

y = (-5/3)x - 5

Step-by-step explanation:

5x + 3y = =15

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divide both sides by 3:

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a

Step-by-step explanation:

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