Answer:
1.
centre(h,k)=(-13,9)
radius (r)=6
we have
equation of the circle is
(x-h)²+(y-k)²=r²
(x+13)²+(y-9)²=6²
x²+26x+169+y²-18y+81=36
x²+y²+26x-18y+169+81-36=0
x²+y²+26x-18y +214=0
is a required equation of the circle.
2.
centre(h,k)=(1,-1)
radius (r)=11
we have
equation of the circle is
(x-h)²+(y-k)²=r²
(x-1)²+(y+1)²=11²
x²-2x+1+y²+2y+1=121
x²+y²-2x+2y=121-2
x²+y²-2x+2y=119
is a required equation of the circle.
Answer:
In order to find x, you will have to use the operation of equality to isolate the x.
<em>Now, use the division property of equality and divide by 15 on both sides. This will cancel out the 15 on the left side of the equation and isolate the x completely.</em>
<em>Thus, this is your answer:</em>
Answer:
the domain is 5 and the range is 10
Step-by-step explanation:
S1 = 72
S2 = 12 = 72*(1/6)
S3 = 2 = 72*(1/6)^2
.
.
.
S15 = 72*(1/6)^14 = 9.18*10^(-10)
Answer:
volume = 4/3 (pi x r^3)
Volume = 4/3 (pi x 15^3)
Volume = 4/3 (3.14 x 3375)
Volume = 14130 cubic cm
Step-by-step explanation:
