Ask question

Ask question

All categories

3 years ago

13

Help help help help. Help

1 answer:

mylen [45]3 years ago

7 0

Step-by-step explanation:

5w-w/x

=5(6)-6/2

=30-3

=27

You might be interested in

1)Sheyna drive to the lake and back. It took two hours less time to get there than it did to get back. The average speed on the

ipn [44]

Answer:

8 hours

Step-by-step explanation:

Given:

Sheyna drives to the lake with average speed of 60 mph and

$v_1 = 60\ mph$

Sheyna drives back from the lake with average speed of 36 mph

$v_2 = 36\ mph$

It took 2 hours less time to get there than it did to get back.

Let $t_1$ be the time taken to drive to lake.

Let $t_2$ be the time taken to drive back from lake.

$t_2-t_1 = 2$ hrs ..... (1)

To find:

Total time taken = ?

$t_1+t_2 = ?$

Solution:

Let D be the distance to lake.

Formula for time is given as:

$Time =\dfrac{Distance}{Speed }$

$t_1 = \dfrac{D}{60}\ hrs$

$t_2 = \dfrac{D}{36}\ hrs$

Putting in equation (1):

$\dfrac{D}{36}-\dfrac{D}{60} = 2\\\Rightarrow \dfrac{5D-3D}{180} = 2\\\Rightarrow \dfrac{2D}{180} = 2\\\Rightarrow D = 180\ miles$

So,

$t_1 = \dfrac{180}{60}\ hrs = 3 \ hrs$

$t_2 = \dfrac{180}{36}\ hrs = 5\ hrs$

So, the answer is:

$t_1+t_2 = \bold{8\ hrs}$

8 0

3 years ago

A random sample of 38 wheel chair users were asked whether they preferred cushion type A or B, and 28 of them preferred type A w

-BARSIC- [3]

Answer:

The statement that cushion A is twice as popular as cushion B cannot be verified

Step-by-step explanation:

From the question we are told that:

Sample size n=38

Type a size A $X_a=28$

Type a size B $X_b=10$

Generally the probability of choosing cushion A P(a) is mathematically given by

$P(a)=\frac{28}{38}$

$P(a)=0.73$

Generally the equation for A to be twice as popular as B is mathematically given by

$P(b)+2P(b)=3P$

Therefore Hypothesis

$Null H_0: p \leq \frac{2P}{3P} \\Altenative H_A:p>\frac{2P}{3P}$

Generally the equation normal approx of p value is mathematically given by

$z=\frac{x-np_0-0.5}{\sqrt{np_0(1-p_0)} }$

$z=\frac{28-(38*2/3)_0-0.5}{\sqrt{38*2/3*1/3} }$

$z=0.75$

Therefore from distribution table

$Pvalue=1-\theta (0.75)$

$Pvalue=0.227$

Therefore there is no sufficient evidence to disagree with the Null hypothesis $H_0$

Therefore the statement that cushion A is twice as popular as cushion B cannot be verified

7 0

3 years ago

I need help with this one

klio [65]

It is a that is your answer

8 0

3 years ago

Which of these might describe expenses for a student? Select all that apply.

lubasha [3.4K]

Answer:

Foods and shoes thats it

Step-by-step explanation:

8 0

3 years ago

What is 47 minutes before 6:57

Schach [20]

6:10 is 47 mins before 6:57!!

6 0

2 years ago

Read 2 more answers