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3 years ago

7

Given ∆QRS≅∆TUV, QS=4v+3, and TV=7v-9, find the length of QS and TV.?

2 answers:

weqwewe [10]3 years ago

8 0

If <span>∆QRS≅∆TUV, then their corresponding sides would be equal.
so, QS = TV
7v - 9 = 4v + 3
7v - 4v = 3 + 9
3v = 12
v = 12/3
v = 4

Then, QS = 4(4) + 3 = 16 + 3 = 19
& Also, TV = 7(4) - 9 = 28 - 9 = 19

In short, Your Answer would be Option C

Hope this helps!</span>

Anon25 [30]3 years ago

7 0

If we are supposed to assume that QS=TV

4v+3=7v-9
minus 4v both sides
3=3v-9
add 9
12=3v
divide 3
4=v
v=4

sub back

4v+3=QS=TV
4(4)+3=QS=TV
16+3=QS
19=QS=TV

then answer is C

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3 years ago

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3 years ago

Read 2 more answers

Hey, I need help with questions 1 and 2, if anyone can help, please? thanks!

Eva8 [605]

The correct works are:

$Blue(s + h) = 2s^2 + 4sh + 2h^2 + 3$ .
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<h3>Function Notation</h3>

The function is given as:

$Blue(s) = 2s^2 + 3$

The interpretation when Steven is asked to calculate Blue(s + h) is that:

Steven is asked to find the output of the function Blue, when the input is s + h

So, we have:

$Blue(s + h) = 2(s + h)^2 + 3$

Evaluate the exponent

$Blue(s + h) = 2(s^2 + 2sh + h^2) + 3$

Expand the bracket

$Blue(s + h) = 2s^2 + 4sh + 2h^2 + 3$

So, the correct work is:

$Blue(s + h) = 2s^2 + 4sh + 2h^2 + 3$

<h3>Simplifying Difference Quotient</h3>

In (a), we have:

$Blue(s + h) = 2s^2 + 4sh + 2h^2 + 3$

$Blue(s) = 2s^2 + 3$

The difference quotient is represented as:

$\frac{f(x + h) - f(x)}{h}$

So, we have:

$\frac{Blue(s + h) - Blue(s)}{h} = \frac{2s^2 + 4sh + 2h^2 + 3 - 2s^2 - 3}{h}$

Evaluate the like terms

$\frac{Blue(s + h) - Blue(s)}{h} = \frac{4sh + 2h^2}{h}$

Evaluate the quotient

$\frac{Blue(s + h) - Blue(s)}{h} = 4s + 2h$

Hence, the correct work is:

$\frac{Blue(s + h) - Blue(s)}{h} = 4s + 2h$

Read more about function notations at:

brainly.com/question/13136492

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2 years ago

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spin [16.1K]

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Second option is the correct answer.

Step-by-step explanation:

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