Given ∆QRS≅∆TUV, QS=4v+3, and TV=7v-9, find the length of QS and TV.?

2 answers:

8 0

If <span>∆QRS≅∆TUV, then their corresponding sides would be equal.
so, QS = TV
7v - 9 = 4v + 3
7v - 4v = 3 + 9
3v = 12
v = 12/3
v = 4

Then, QS = 4(4) + 3 = 16 + 3 = 19
& Also, TV = 7(4) - 9 = 28 - 9 = 19

In short, Your Answer would be Option C

Hope this helps!</span>

Anon25 [30]3 years ago

7 0

If we are supposed to assume that QS=TV

4v+3=7v-9
minus 4v both sides
3=3v-9
add 9
12=3v
divide 3
4=v
v=4

sub back

4v+3=QS=TV
4(4)+3=QS=TV
16+3=QS
19=QS=TV

then answer is C

You might be interested in

PLEASE ANSWER QUICKLY I WILL MARK BRAINIEST AND 70 POINT

kykrilka [37]

a) You are given the rate as 7.4m/min,

The equation would become d = 7.4t where d is the total distance and t would be the total number of minutes.

b) d would be a positive number because the diver is ascending, which means he is moving up towards the surface.

c) To find how long it took the diver, replace d with 41.36 ( how deep the diver was) and solve for t:

41.36 = 7.4t

To solve for t, divide both sides by 7.4:

t = 41.36 / 7.4

t = 5.59 minutes ( 5 minutes and 35 seconds)

8 0