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Shtirlitz [24]
3 years ago
7

Given ∆QRS≅∆TUV, QS=4v+3, and TV=7v-9, find the length of QS and TV.?

Mathematics
2 answers:
weqwewe [10]3 years ago
8 0
If <span>∆QRS≅∆TUV, then their corresponding sides would be equal.
so, QS = TV
7v - 9 = 4v + 3
7v - 4v = 3 + 9
3v = 12
v = 12/3
v = 4

Then, QS = 4(4) + 3 = 16 + 3 = 19
& Also, TV = 7(4) - 9 = 28 - 9 = 19

In short, Your Answer would be Option C

Hope this helps!</span>
Anon25 [30]3 years ago
7 0
If we are supposed to assume that QS=TV

4v+3=7v-9
minus 4v both sides
3=3v-9
add 9
12=3v
divide 3
4=v
v=4

sub back

4v+3=QS=TV
4(4)+3=QS=TV
16+3=QS
19=QS=TV

then answer is C
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Step-by-step explanation:

<u>Step 1: Define</u>

x² - 8x + 15 = 0

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. [Subtraction Property of Equality] Subtract 15 on both sides:                     x² - 8x = -15
  2. Complete the Square [Addition Property of Equality]:                                 x² - 8x + 16 = -15 + 16
  3. [Complete the Square] Simplify:                                                                   (x - 4)² = 1
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  5. [Addition Property of Equality] Add 4 on both sides:                                   x = 4 ± 1
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S_A_V [24]

Answer:

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