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slava [35]
3 years ago
13

A kite has vertices at (2, 4), (5, 4), (5, 1), and (0, –1).

Mathematics
2 answers:
JulsSmile [24]3 years ago
7 0
The answer is 16.8 units
REY [17]3 years ago
3 0

Answer:

16.7 units

Step-by-step explanation:

We are given that A kite has vertices at (2, 4), (5, 4), (5, 1), and (0, –1).

So, Let A = (2,4)

B =(5,4)

C =(5,1)

D =(0,-1)

So, Find the sides AB ,BC,CD,AC

To find AB use distance formula :

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

(x_1,y_1)=(2,4)

(x_2,y_2)=(5,4)

Substitute the values in the formula :

AB=\sqrt{(5-2)^2+(4-4)^2}

AB=\sqrt{(3)^2+(0)^2}

AB=\sqrt{9}

AB=3

To find BC use distance formula :

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

(x_1,y_1)=(5,4)

(x_2,y_2)=(5,1)

Substitute the values in the formula :

BC=\sqrt{(5-5)^2+(1-4)^2}

BC=\sqrt{(0)^2+(-3)^2}

BC=\sqrt{9}

BC=3

To find CD use distance formula :

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

(x_1,y_1)=(5,1)

(x_2,y_2)=(0,-1)

Substitute the values in the formula :

CD=\sqrt{(0-5)^2+(-1-1)^2}

CD=\sqrt{(-5)^2+(-2)^2}

CD=\sqrt{25+4}

CD=\sqrt{29}

To find AD use distance formula :

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

(x_1,y_1)=(2,4)

(x_2,y_2)=(0,-1)

Substitute the values in the formula :

CD=\sqrt{(0-2)^2+(-1-4)^2}

CD=\sqrt{(-2)^2+(-5)^2}

CD=\sqrt{4+25}

CD=\sqrt{29}

Now perimeter of Kite = Sum of all sides

                                     =AB+BC+CD+AD

                                    = 3+3+\sqrt{29}+\sqrt{29}

                                    = 16.7

Thus the perimeter of the kite is 16.7 units.

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Answer:

Step-by-step explanation:

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5 0
3 years ago
If a ball is thrown into the air with a velocity of 48 ft/s, its height in feet t seconds later is given by y = 48t − 16t2. Find
dimaraw [331]
The formula for average velocity between two times t1 and t2 of the position function f(x) is (f(t2)-f(t1)) / (t2-t1)
Plugging the values in for the first time period we get (f(2.5)-f(2)) / (2.5-2)
=> (f(2.5)-f(2)) / 0.5
f(2) will be the same for all 4 time periods and is
48(2)-16(2)^2 = 32
Now we plugin the other values
f(2.5) = 48(2.5)-16(2.5)^2 = 20
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Final answer:
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