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igor_vitrenko [27]
3 years ago
7

. Convert 4.0 kilometers (km) to meters (m). (1 point) 0.04 m 40 m 400 m 4,000 m

Mathematics
1 answer:
kvasek [131]3 years ago
6 0
Four kilometers into meters is 4,000 meters.
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PLEASE ANSWER THIS QUESTION <br>Show that 4x – 7 is equivalent to 4(x - 1) – 3 when x = 3.​
Drupady [299]

Answer:

4(3) - 7 = 4(3 - 1) - 3

12 - 7 = 4(2) - 3

5 = 8 - 3

= 5

They are equivalent because when they are both simplified they have the same answer 5

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3 years ago
What is the area of this figure?<br><br> Enter your answer in the box.
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The parallelogram is 45 square meters. Multiply the base by the height. The triangle is 36 square meters. Multiply the base by the height and divide by two. Thus, the answer is 81.
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3 years ago
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Whenever 2 line or intersect at 90 the 2 lines are said to be ?
Sedaia [141]
Two lines that intersect at 90 degrees are considered perpendicular to each other.

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9. If each of the following pairs represents a pair of equivalent rational
Oksi-84 [34.3K]

Answer:

-35/6

Step-by-step explanation:

We need to find the value of x , And the given pair of Rational numbers are equal.

<u>Question</u><u> </u><u>(</u><u>I)</u><u> </u><u>:</u><u>-</u><u> </u>

→ 3/4 = 7/x

→ 7/x = 3/4

→ 1/x = 3/4 × 1/7

→ 1/x = 3/28

→ x = 28/3

<u>Question</u><u> (</u><u>ii)</u><u> </u><u>:</u><u>-</u><u> </u>

→ x/7 = -5/6

→ x = -5/6 × 7

→ x = -35/6

<h3>• Hence the value of x is -35/6 .</h3>
7 0
2 years ago
For what value of the constant c is the function fcontinuous on (−[infinity], [infinity])?
Arlecino [84]

Answer:

For c=\frac{1}{7} the function f(x) is continuous on (-\infty,\infty).

Step-by-step explanation:

We have the following function

f(x) = \left\{        \begin{array}{ll}            cx^2+5x & \quad x

For the function f(x) to be continuous on (-\infty,\infty) it is sufficient to have continuity at x = 6, we need to ensure that as x approaches 6, the left and right limits match, this means that

\lim_{x \to 6^{-} } f(x)=\lim_{x \to 6^{+} } f(x)=f(x),

which holds if and only if

c\left(6\right)^2+5\left(6\right)=\left(6\right)^2-c\left(6\right)\\36c+30=36-6c\\42c=6

namely if c=\frac{1}{7}.

6 0
2 years ago
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