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Mice21 [21]
3 years ago
9

Please help thank you

Mathematics
1 answer:
Nana76 [90]3 years ago
8 0

Answer:

Domain: {-1,-2,-3,-4}

Range: {4,5}

Step-by-step explanation:

As the range has repeated numbers, you don't have to repeat them.

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Find the slope (-2,-4) (-5,5)
diamong [38]

Answer:

Your answer would be Slope m = -3

Step-by-step explanation:

Step 1: Graph the points on a <u>coordinate plane</u>( <em>refer to image!)</em>

Whenever your trying to find a slope of 2 order pairs, remember this

m = rise/run. ( Slope = rise over run.) = Δy/Δx

Now we solve:

M = rise/run = Δy/Δx

M = y2 - y1/x2-x1

M = 5 - (-4) / -5-(-2)

<u>So we get  M = 9/-3 and </u><u>9 divided by -3 is -3 </u>

<u />

So, the slope of (-2,-4) and (-5,5) is -3.

5 0
2 years ago
If angle symbol1 and angle symbol2 are complementary angles and if the measure of angle symbol1 is 5454degrees° more than the me
Misha Larkins [42]
<span>Complementary angles by definition sum up to 90 degrees.
   Let x = measure of angle2.
 It's given that angle1 = x + 54

   Since complementary, we know (x+54)+x = 90
 2x+54=90
 2x=36
 x=18.
 So angle2 measures 18 degrees and angle1 is 18 degrees+54 degrees, or 72 degrees. 72+18 = 90 as expected for complementary angles.</span>
7 0
3 years ago
Round 0.172 to the nearest hundredth.
aleksandr82 [10.1K]
It is <span>Round 0.172 to the nearest hundredth.</span>
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3 years ago
Read 2 more answers
Can someone make sure that I’m right
WARRIOR [948]

Answer:

A

Step-by-step explanation: You are correct!

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3 years ago
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This is a pre calculus question that I need help with, serious answer PLEASE and thank you! Will give brainliest.
IRISSAK [1]

The wording of this question is a bit confusing... You can't write a sequence in sigma notation, but rather a series or sum. I think the question is asking you to write the sum of the sequence,

\dfrac12,\dfrac14,\dfrac18,\ldots,\dfrac1{64}

which would be

\dfrac12+\dfrac14+\dfrac18+\cdots+\dfrac1{64}

in sigma notation.

To do this, notice that the denominator in each term is a power of 2, starting with 2^1=2 and ending with 2^6=64. So in sigma notation, this series is

\displaystyle\sum_{n=1}^6\frac1{2^n}

4 0
3 years ago
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