Answer:
B
Step-by-step explanation:
Answer:
<em>-1</em>
Step-by-step explanation:
1. A water wheel rung’s height as a function of time can be modeled by the equation:
h - 8 = -9 sin6t
(b) Determine the maximum height above the water for a rung.
Given the rung's height modeled by the equation;
h - 8 = -9 sin6t
h(t) = -9sin6t + 8
At maximum height, the velocity of the rung is zero;
dh/dt = 0
dh/dt = -54cos6t
-54cos6t = 0
cos6t = 0/-54
cos6t = 0
6t = cos^-1(0)
6t = 90
t = 90/6
t= 15
Substitute t = 15 into the expression to get the maximum height;
Recall:
h(t) = -9sin6t + 8
h(15) = -9sin6(15) + 8
h(15) = -9sin90 + 8
h(15) = -9(1)+8
h(15) = -9+8
<em>h(15) = -1</em>
<em>hence the maximum height above the water is -1</em>
Answer:
x^2+11x+30
Step-by-step explanation:
This is a parallelogram.
Area of a parallelogram can be found with:
A=bh
Plug our values in.
A=(x+6)(x+5)
FOIL-
First: x*x=x^2
Outside: x*5=5x
Inside: 6*x=6x
Last: 6*5=30
x^2+5x+6x+30
Combine like terms.
x^2+11x+30
Answer:
The correct answer is B. 2/3 < 3/4.
