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3 years ago

Helppp ill give you brainliest

Mathematics

2 answers:

Evgen [1.6K]3 years ago

7 0

Answer is c+3

the question asks for the sum, the sum comes from addition. therefore, the answer is c+3

Ymorist [56]3 years ago

6 0

Answer:

Step-by-step explanation:

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In a study of towns, there was a positive correlation between the number of mail boxes and number of traffic lights in a town.

topjm [15]

Population, because the more people there are in a town, the more mailboxes and traffic lights there will be. There will have to be more in order to supply the population.

4 0

3 years ago

Read 2 more answers

Show how the following sequences is an arithmetic or not <br>please help me

serious [3.7K]

Answer:

not arithmetic

Step-by-step explanation:

An arithmetic sequence has a common difference d between consecutive terms.

Given

$T_{n}$ = 2n² - 1

Substitute in n = 1, 2, 3, 4 to generate the first 4 terms of the sequence

$T_{1}$ = 2(1)² - 1 = 2 - 1 = 1

$T_{2}$ = 2(2)² - 1 = 8 - 1 = 7

$T_{3}$ = 2(3)² - 1 = 18 - 1 = 17

$T_{4}$ = 2(4)² - 1 = 32 - 1 = 31

check the difference between consecutive terms

7 - 1 = 6

17 - 7 = 10

31 - 17 = 14

The differences are not common hence not an arithmetic sequence

5 0

4 years ago

Graph the function <br><br> x+y=0

Dimas [21]

Answer:

Step-by-step explanation:

6 0

3 years ago

Please dont ignore, Need help!!! Use the law of sines/cosines to find..

Ket [755]

Answer:

16. Angle C is approximately 13.0 degrees.

17. The length of segment BC is approximately 45.0.

18. Angle B is approximately 26.0 degrees.

15. The length of segment DF "e" is approximately 12.9.

Step-by-step explanation:

By the law of sine, the sine of interior angles of a triangle are proportional to the length of the side opposite to that angle.

For triangle ABC:

$\sin{A} = \sin{103\textdegree{}}$ ,
The opposite side of angle A $a = BC = 26$ ,
The angle C is to be found, and
The length of the side opposite to angle C $c = AB = 6$ .

$\displaystyle \frac{\sin{C}}{\sin{A}} = \frac{c}{a}$ .

$\displaystyle \sin{C} = \frac{c}{a}\cdot \sin{A} = \frac{6}{26}\times \sin{103\textdegree}$ .

$\displaystyle C = \sin^{-1}{(\sin{C}}) = \sin^{-1}{\left(\frac{c}{a}\cdot \sin{A}\right)} = \sin^{-1}{\left(\frac{6}{26}\times \sin{103\textdegree}}\right)} = 13.0\textdegree{}$ .

Note that the inverse sine function here $\sin^{-1}()$ is also known as arcsin.

By the law of cosine,

$c^{2} = a^{2} + b^{2} - 2\;a\cdot b\cdot \cos{C}$ ,

where

$a$ , $b$ , and $c$ are the lengths of sides of triangle ABC, and
$\cos{C}$ is the cosine of angle C.

For triangle ABC:

$b = 21$ ,
$c = 30$ ,
The length of $a$ (segment BC) is to be found, and
The cosine of angle A is $\cos{123\textdegree}$ .

Therefore, replace C in the equation with A, and the law of cosine will become:

$a^{2} = b^{2} + c^{2} - 2\;b\cdot c\cdot \cos{A}$ .

$\displaystyle \begin{aligned}a &= \sqrt{b^{2} + c^{2} - 2\;b\cdot c\cdot \cos{A}}\\&=\sqrt{21^{2} + 30^{2} - 2\times 21\times 30 \times \cos{123\textdegree}}\\&=45.0 \end{aligned}$ .

For triangle ABC:

$a = 14$ ,
$b = 9$ ,
$c = 6$ , and
Angle B is to be found.

Start by finding the cosine of angle B. Apply the law of cosine.

$b^{2} = a^{2} + c^{2} - 2\;a\cdot c\cdot \cos{B}$ .

$\displaystyle \cos{B} = \frac{a^{2} + c^{2} - b^{2}}{2\;a\cdot c}$ .

$\displaystyle B = \cos^{-1}{\left(\frac{a^{2} + c^{2} - b^{2}}{2\;a\cdot c}\right)} = \cos^{-1}{\left(\frac{14^{2} + 6^{2} - 9^{2}}{2\times 14\times 6}\right)} = 26.0\textdegree$ .