Answer:
10 cuadrados
Step-by-step explanation:
Si uno de los lados de rectangulo es de 4cm entonces el lado parallelo tambien es de 4cm. Eso nos da 8cm del perimetro y nos quedan los otros dos lados que tienen la misma medida. Entonces dividimos el resto del perimetro por 2.
28 - 8 = 20cm
20cm / 2cm = 10cm
Ahora que tenemos todas las medidas podemos multiplicar el largo por el ancho para calcular el area del rectangulo
10cm * 4cm = 40
el cuadrado de 2cm tendra un area de
2cm * 2cm = 4
Ahora simplemente dividimos el area del rectangulo por el area del cuadrado para saber cuantos cuadrados necesitamos para armar ese rectangulo
40 / 4 = 10 cuadrados
Answer:
The correct option is A. x – 1 < n < 3x + 5
Step-by-step explanation:
In a triangle sum of any two sides is always greater than the third side.
Now, the sides of the triangle are given to be :
2x + 2, x + 3 , n
Now, first take 2x + 2 and x + 3 as two sides and the side of length n as third side.
By using the property that sum of two sides is always greater than the third side in a triangle.
⇒ 2x + 2 + x + 3 > n
⇒ 3x + 5 > n ......(1)
Now, take n and x + 3 as two sides and the side of length 2x + 2 as the third side of triangle.
So, by the property, we have :
n + x + 3 > 2x + 2
⇒ n > x - 1 ...........(2)
From both the equations (1) and (2) , We get :
x – 1 < n < 3x + 5
Therefore, The correct option is A. x – 1 < n < 3x + 5
Answer:
expoential
Step-by-step explanation:
Answer:
-30bc + 50bd
Step-by-step explanation:
3a + 5b/3c - 5d = 3a - 5b/3c - 5d
(3c - 5d)(3a - 5b) = (3a + 5b)(3c - 5d)
9ca - 15bc - 15da + 25db = 9ac - 15ad + 15bc - 25bd
9ca -15bc - 15da + 25db - 9ac + 15ad - 15bc + 25bd
9ca and -9ac and -15da and 15ad cancel each other out, so
-30bc + 50db is left
<u><em>0.00266666667</em></u> m / min.
