Answer: 54
Step-by-step explanation:
First we add 17 plus 18 to dins total number of students I got 35
Then we make ratio
3/35
So we know we have total number of 630 kids then we make a ratio with no teacher so x
X/630
Lin both together then done ☑️
Answer:
0.0111% probability that he answers at least 10 questions correctly
Step-by-step explanation:
For each question, there are only two outcomes. Either it is answered correctly, or it is not. The probability of a question being answered correctly is independent from other questions. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
A multiple-choice examination has 15 questions, each with five answers, only one of which is correct.
This means that 
What is the probability that he answers at least 10 questions correctly?









0.0111% probability that he answers at least 10 questions correctly
Answer: a. It is commonly referred to as the arithmetic average.
b. It is algebraically defined (that is, there is an equation you can use to calculate its value).
c. It is easily influenced by extreme scores.
Step-by-step explanation:
The mean is also referred to as the "average" and it is gotten by adding every number and the dividing the value gotten by the number of the numbers used for the calculation.
It should be noted that the mean is algebraically defined and can be easily influenced by extreme scores.
5 meters/ 1 second because if you 40 and 8 you will get 5 and divided 8 by 8 and you get 1, you just divide the denominator by both numerator and denominator.
I am pretty sure it is 0.064. Hope this helps