Answer:
50%
Step-by-step explanation:
I'll do Problem 8 to get you started
a = 4 and c = 7 are the two given sides
Use these values in the pythagorean theorem to find side b

With respect to reference angle A, we have:
- opposite side = a = 4
- adjacent side = b =

- hypotenuse = c = 7
Now let's compute the 6 trig ratios for the angle A.
We'll start with the sine ratio which is opposite over hypotenuse.

Then cosine which is adjacent over hypotenuse

Tangent is the ratio of opposite over adjacent

Rationalizing the denominator may be optional, so I would ask your teacher for clarification.
So far we've taken care of 3 trig functions. The remaining 3 are reciprocals of the ones mentioned so far.
- cosecant, abbreviated as csc, is the reciprocal of sine
- secant, abbreviated as sec, is the reciprocal of cosine
- cotangent, abbreviated as cot, is the reciprocal of tangent
So we'll flip the fraction of each like so:

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Summary:
The missing side is 
The 6 trig functions have these results

Rationalizing the denominator may be optional, but I would ask your teacher to be sure.
Hello!
You have to find the area of the first rectangle
13 * 25 = 325
Next find the area of the second rectangle
The base is quadripled
13 * 4 = 52
52 * 25 = 1300
Divide the area of rectangle 2 by the area of rectangle 1
1300/ 325 = 4
The answer is D. 4 times bigger
Hope this helps!
3 & 3
Can someone help me with this