Please HELP! I will mark best answer as brainliest

Mathematics

1 answer:

elena-s [515]2 years ago

8 0

Its decreased by 200 in the 4 years from 1994 to 1998 That is 50 less per year
In 1990 the population would have been 2500
So the required formula is

P = -50t + 2500 ( or you could write it as P = 2500 - 50t

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Find the length of l on the curve r(t)=5cos(3t)i-5sin(3t)j+3tk over the interval [3,7]

stealth61 [152]

$\mathbf r(t)=5\cos3t\,\mathbf i-5\sin3t\,\mathbf j+3t\,\mathbf k$
$\mathrm d\mathbf r(t)=\mathbf r'(t)\,\mathrm dt=(-15\sin3t\,\mathbf i-15\cos3t\,\mathbf j+3\,\mathbf k)\,\mathrm dt$

$\displaystyle\int_C\mathrm d\mathbf r(t)=\int_{t=3}^{t=7}\|\mathbf r'(t)\,\mathrm dt\|=\int_{t=3}^{t=7}\sqrt{225\sin^23t+225\cos^23t+9}\,\mathrm dt$
$=\displaystyle3\sqrt{26}\int_{t=3}^{t=7}\mathrm dt$
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4 0

3 years ago

HELP ME ASAP PLS.......

Sergio [31]

Answer:

Step-by-step explanation: 32

3 0

2 years ago

3. A piece of white oak has a densityof 0.77 g/cm and a mass of 100 g,what would be the volume of thesample? PLEASE HELP!

Nezavi [6.7K]

$\text{Volume}=129.87cm^3$

Explanation

Step 1

the density of an object is given by:

$\text{density}=\text{ }\frac{mass}{\text{volume}}$

Step 2

let

$\begin{gathered} \text{density}=0.77\frac{g}{cm^3} \\ \text{mass}=\text{ 100 g} \\ \end{gathered}$

Step 3

replace,

$\begin{gathered} \text{density}=\text{ }\frac{mass}{\text{volume}} \\ 0.77\frac{g}{cm^3}=\frac{100g}{\text{volume}} \\ \text{volume}\cdot0.77\frac{g}{cm^3}=\text{1}00\text{ g} \\ \\ \text{Volume}=\frac{100\text{ g}}{0.77\frac{g}{cm^3}} \\ \text{Volume}=129.87cm^3 \end{gathered}$

I hope this helps you

5 0

1 year ago

Just list all of the possible answers

Genrish500 [490]

Answer:

what grade are you??........

8 0

1 year ago

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What is the ? in this pattern <br><br><br> 3, -6, 12, 4, 20, ?

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