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Gemiola [76]
3 years ago
15

The median of the data set is 81. what number is missing? 82, 87, __, 77, 70, 80, 88

Mathematics
1 answer:
11111nata11111 [884]3 years ago
8 0
The number that is missing is 83
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ASAP please help!!!
Serggg [28]
Y+4<u><</u>9
subtract 4
y<u><</u>5
y is smaller than and equal to 5
so you shade from 5 to the negative end to infinity (to the left) and shade the 5 to show that it is included (attachment says A)







6 less than (-6) 2 times a number (2 time x) is greater than (>) 8 (8)

-6+2x>8
add 6
2x>14
divide 2
x>7
so
x is bigger than 7
shade from 7 to the positive end to infinity (to the right) and don't shade 7 but put a circle around it to show that it is not included (attachment says B )

I have included pictures of the number lines

4 0
3 years ago
Solve the inequality <br> 29-2(3-5w) 13
valentinak56 [21]

Answer:

29-2(2w)13

29-2(26w)

29-52w

w=52÷29

7 0
3 years ago
Please Help! (Math)(tanβ)
sertanlavr [38]

Answer:

<u>Find the missing side first.</u>

  • x = \sqrt{12^2 - 7^2}  = \sqrt{144 - 49} = \sqrt{ 95}

1) tangent = opposite leg / adjacent leg

  • tanβ = √95/7
  • Correct choice is B

2) sine = opposite leg / hypotenuse

  • sinβ = √95/12
  • Correct choice is D
7 0
2 years ago
If s(x) = x – 7 and t(x) = 4x2 – x + 3, which expression is equivalent to
Vlada [557]
The answer is If you would like to find the expression that is equivalent to (t*s)(x), you can calculate this using the following steps:

s(x) = x - 7
t(x) = 4x^2 - x + 3

(t*s)(x) = t(s(x)) = t(x - 7) = <span>4(x - 7)^2 - (x - 7) + 3 = 4(x - 7)^2 - x + 7 + 3

The correct result would be </span>4(x – 7)2 – (x – 7) + 3.
6 0
3 years ago
The numerator and denominator of a fraction are in the ratio of 3 to 5. If the numerator and denominator are both increased by 2
ivolga24 [154]

Question:

The numerator and denominator of a fraction are in the ratio of 3 to 5. If the numerator and denominator are both decreased by 2, the fraction is now equal to  \frac{1}{2}.

If n = the numerator and d = the denominator, which of the following systems of equations could be used to solve the problem?

5n = 3d and n - 2 = 2d - 4

5n = 3d and 2n - 4 = d - 2

3n = 5d and 2n - 4 = d - 2

Answer:

5n = 3d and 2n – 4 = d – 2

Solution:

Let n be the numerator of the fraction and d be the denominator of the fraction.

Given the numerator and denominator of a fraction are in the ratio of 3 to 5.

This can be written as n : d = 3 : 5.

⇒ \frac{n}{d}= \frac{3}{5} – – – – (1)

Do cross multiplication, we get

⇒ 5n = 3d

When the numerator and denominator are decreased by 2, the fraction is equal to \frac{1}{2}.

⇒ \frac{n-2}{d-2}= \frac{1}{2}

Do cross multiplication, we get

⇒ 2(n –2)=1(d – 2)

⇒ 2n – 4 = d – 2

Hence, 5n = 3d and 2n – 4 = d – 2 can be used to solve the problem.

6 0
3 years ago
Read 2 more answers
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