Alright, so you have the basic formula- good.
You have the A value (400), the interest rate r (7.5% -> .075 in decimal), and the final P value (8500). So, we only need to solve for t.
8500 = (400)(1+.075)^t
/400 /400
21.25 = 1.075^t
logarithms are the inverse of exponents, basically, if you have an example like
y = b^x, then a logarithm inverts it, logy(baseb)=x
Makes sense if you consider a power of ten.
1000 = 10^3
if you put logbase10(1000), you'll get 3.
Anyways, though, to solve the problem make a log with a base of 1.075 in your calculator
log21.25(base 1.075) = t
also, because of rules of change of base (might want to look this up to clarify), you can write this as log(21.25)/log(1.075) = t
Thus, t is 42.26118551.
Rounded to hundredths, t=42.26
Answer:
The answer is -2/3.
Hope this helps and if you could mark as brainliest. Thanks!
Answer:
D
Step-by-step explanation:
I hope this is correct!
Answer:
14 more flower would bloom if 21 more tulip bulb is planted.
Step-by-step explanation:
Given ratio for tulip bulbs and flowers is 15:10.
Now, finding number of flower to bloom if 21 tulip bulb are planted.
Assume if 21 tulip bulbs are planted then number of flower would bloom be"x"
ratio given: 
Cross multiplying the ratio to get:
⇒x= 
∴
Hence, 14 flowers would bloom if 21 tulip bulb are planted.
If total tulip bulb is 
, then 
would bloom.
Answer:
C
Step-by-step explanation:
Dot plot is usually in the form of stem & leaf. The only difference is that, stem& leaf presents the actual values while dot plot usually represent the value in dots. Hence, we can easily generate dot plot from stem & leaf!
For (a) dot plot and box plot, dot plot presents all the data while box plot presents only the five-num statistics, namely:
1. minimum
2. 1st quartile (Q1)
3. median
4. 3rd quartile (Q3)
5. Maximum
And outliers, if any!
Thus, dot plot cannot directly generate box plot
For (b). Histogram and stem & leaf. Although both usually help us understand the skewness of data distribution, however, histogram deals with frequency distribution (counts of number of occurrence) and plotted on the intervals and stem&leaf list the values.
For (d). Even though dot plot shoots up and down like the histogram, the content is different. In dot plot, it is the actual value represented in dots. But in histogram, it is the frequency distribution of the class intervals.
