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Tomtit [17]
4 years ago
14

The vet told Jake that his dog, Rocco, who weighed 55 pounds, needed to lose 10 pounds. Jake started walking Rocco every day and

changed the amount of food he was feeding him. Rocco lost half a pound the first week. Jake wants to determine Rocco’s weight in pounds, p, after w weeks if Rocco continues to lose weight based on his vet’s advice.
Mathematics
2 answers:
madreJ [45]4 years ago
6 0

Answer:it would take him five weeks to lose ten pounds

Step-by-step explanation:

Lesechka [4]4 years ago
5 0

Answer: To determine Rocco´s weight jake must use this expression

  • p = 55 - 0.5 w

Step-by-step explanation:

Hi to solve this problem we have to analyze the information given:

  • Rocco´s initial weight: 55 pounds
  • Pounds lost per week: 0.5 pounds  

So, we have to write an equation where p is Rocco's weight after w weeks.

Each week Rocco will lose 0.5 pounds so the expression is 0.5w, where w is the number of weeks.

Mathematically speaking:

  • p = 55 - 0.5 w

By replacing w by the number of weeks, Jake will obtain Rocco´s weight.

For example, if the number of weeks is 20:

p= 55-0.5x 10

p= 55 - 20

p= 35

After 20 weeks Rocco will lose 10 pounds.

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liraira [26]

Answer:

The length of a side of the flag is 7.2inches

Step-by-step explanation:

Let length = x

Let hypotenuse = x+3

Using Pythagoras' Theorem:

x^2 + x^2 = (x+3)^2

x^2 + x^2 = x^2 + 6x + 9

2x^2 = x^2 + 6x + 9

×^2 - 6x - 9 = 0

x =  \frac{ - b +  -  \sqrt{ {b}^{2} - 4ac } }{2a}

x=[-(-6)+sqrt.(-6)^2-4(1)(-9)]/2(1)

×=[6+sqrt.72]/2

×=7.2inches

×=[-(-6)+sqrt.(-6)^2-4(1)(-9)]/2(1)

x=[6-sqrt.72]/2

×=-1.2(rej)

(PS. sqrt is square root)

(Correct me if i am wrong)

6 0
3 years ago
Read 2 more answers
the vertex of this parabola is at (3,-2). When the x-vaue is 4, the y-value is 3. What is the coefficient of the squared express
bixtya [17]
<h3>Answer:   5</h3>

=========================================================

Explanation:

Vertex form is

y = a(x-h)^2 + k

We are told the vertex is (3,-2), so we know (h,k) = (3,-2)

y = a(x-h)^2 + k will update to y = a(x-3)^2 - 2

--------

Then we also know that (x,y) = (4,3) is a point on the parabola. Plug those x and y values into the equation and solve for 'a'

y = a(x-3)^2 - 2

3 = a(4-3)^2 - 2

3 = a(1)^2 - 2

3 = a - 2

3+2 = a

5 = a

a = 5

This is the coefficient of the x^2 term since the standard form is y = ax^2+bx+c.

4 0
3 years ago
COSS SENSE-MAKING The sides of square ABCD are extended
dsp73

Answer: 9 in

Step-by-step explanation:

5 0
3 years ago
Stacey has a part time job , she earns £8 an hour.
Sedaia [141]

Answer:

Step-by-step explanation:

220/8=27.5

28 hours

8 0
3 years ago
(7 * 10-5) (5 x 10-) =<br><br>x 10​
blagie [28]

Have you learned PEMDAS? (Parenthesis, exponents, multiplication, division, addition, subtraction). That is what I am going to do here.

The first parenthesis, let's solve. 7*10=70-5=65

The second parentheisis: I am assuming the negative sign is a typo, and this answer will be off if it is not. Sorry. 5*10=50

65*50=3250

I hope this helps, and let me know if you need further assistance.

8 0
3 years ago
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