Answer:
74.86% probability that a component is at least 12 centimeters long.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
Variance is 9.
The standard deviation is the square root of the variance.
So
Calculate the probability that a component is at least 12 centimeters long.
This is 1 subtracted by the pvalue of Z when X = 12. So
has a pvalue of 0.2514.
1-0.2514 = 0.7486
74.86% probability that a component is at least 12 centimeters long.
Total number of marble = 10
3green
2red
5 blue
Probability that the first marble is red = 2/10
Probability that the second is blue = 5/9(a reduction in the total number of marbles, because after the first marble was picked it wasn't replaced)
Probability of 1st and 2nd being red and blue respectively = 2/10 × 5/9
=1/9....
Hope this helped...?
Answer:
C.
Step-by-step explanation:
Hope this helps! :)
Step-by-step explanation:
Let's solve your equation step-by-step.
2(x+2)−3(x−3)=x+7
Step 1: Simplify both sides of the equation.
2(x+2)−3(x−3)=x+7
(2)(x)+(2)(2)+(−3)(x)+(−3)(−3)=x+7(Distribute)
2x+4+−3x+9=x+7
(2x+−3x)+(4+9)=x+7(Combine Like Terms)
−x+13=x+7
−x+13=x+7
Step 2: Subtract x from both sides.
−x+13−x=x+7−x
−2x+13=7
Step 3: Subtract 13 from both sides.
−2x+13−13=7−13
−2x=−6
Step 4: Divide both sides by -2.
−2x
−2
=
−6
−2
x=3
Answer:
x=3
Answer:
The value of each of the other two numbers is 110.12
Step-by-step explanation:
244.84 - 24.6 = 220.24
220.24 divided by half is 110.12
The value of the other two numbers is 110.12
