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2 years ago

Write a polynomial function of least degree with integral coefficients that has the given zeros. –2, –3,3 – 6i

1 answer:

5 0

$(x-(-2))(x-(-3))(x-(3-6i)(x-(3+6i))=\\(x+2)(x+3)(x-3+6i)(x-3-6i)=\\(x^2+3x+2x+6)((x-3)^2+36)=\\(x^2+5x+6)(x^2-6x+9+36)=\\(x^2+5x+6)(x^2-6x+45)=\\x^4-6x^3+45x^2+5x^3-30x^2+225x+6x^2-36x+270=\\x^4-x^3+21x^2+189x+270$

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alexandr402 [8]

We use ratio and proportion to solve each of these:

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3. The scale factor for a model is 5 cm = ________ m Model : 72.5 cm actual: 165.3 m
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4. The scale of a map is 1 in = 9.6 mi map: ________ in actual: 34.7 mi
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5. The scale of a map is 1 ft = 9.6 mi map: ________ ft actual: 38.4 mi
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6. The scale factor for a model is 5 cm = ________ m Model : 22.4 cm actual: 155.2 m
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7. The scale of a map is 5 in = 10 mi map: 8.7 in actual: ______ mi
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8. The scale of a map is 1 in = 13.5 mi map: ________ in actual: 65.9 mi
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9. The scale factor for a model is 5 cm = ________ m Model : 61.5 cm actual: 143.2 m
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3 years ago

A ruler is 12 inches long.what is the length of this ruler in centimeters

lawyer [7]

I think it is 30.48 because i looked it up

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3 years ago

Read 2 more answers

For what value of n is In - 11 + 1 equal to 1?

Leviafan [203]

It would be 11 if I’m reading this right

8 0

2 years ago

Iliana is painting a picture. She has green, red, yellow, purple, orange, and blue paint. She wants her painting to have four di

ivanzaharov [21]

The number of ways for which she could pick four colours if green must be one of them is; 10 ways.

<h3>How many ways can she picks four colours if green must be there?</h3>

It follows from the task that there are 6 colours in total that she could pick from.

Hence, since she needs four colours with green being one of them, it follows that she only has 3 colours to pick from 5.

Hence, the numbers of possible combinations is; 5C3 = 10 ways.

Read more on combinations;

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5 0

1 year ago

Can somebody help me with this?

Natasha_Volkova [10]

Step-by-step explanation:

Hey there!

By looking through figure, l and m are parallel lines and a transversal line passes through the lines.

Now,

7x + 12° = 12x - 28°( alternate angles are equal)

12°+28° = 12x - 7x

40° = 5x

$x = \frac{40}{5}$

Therefore, x = 8°

Now,

12x - 28° + 9y - 77 = 180° ( being linear pair)

12×8° - 28° + 9y -77° = 180°

96° - 28° + 9y - 77° = 180°

-9 + 9y = 180°

9y = 180° + 9°

y = 189°/9

Therefore, y = 21°

Therefore, X = 8° and y= 21° .

Hope it helps....

4 0

3 years ago