If f(x)=2^x and g(x)=2^x+4 -5 explain how the graph g(x) has been transformed from the graph of f(x) ?

What is the x-value at which the graphs of y = x2 – 2x + 1 and y = x2 + 2x – 7 inter- sect?

Kitty [74]

Answer:

x = 2

Step-by-step explanation:

Both equations are equal to y, so they're also equal to each other. We then set them equal to each other:

x^2 - 2x + 1 = x^2 + 2x - 7

We now do algebra to isolate x. Subtract 1 from both sides.

x^2 - 2x = x^2 + 2x - 8

Subtract 2x from both sides.

x^2 - 4x = x^2 - 8

Subtract x^2 from both sides.

-4x = -8

Divide both sides by -4.

x = 2

5 0

3 years ago

Please help

svp [43]

Answer:

(x + 2)^2 + (y + 2)^2 = 16

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

The map shows the location of the mall, library, and school in the city; Brittany travels from the school to the mall and then f

Shkiper50 [21]

Answer:A) 8 miles

Step-by-step explanation:

8 miles

7 0

2 years ago

When running a 100 meter race Bill reaches his maximum speed when he is 45 meters from the starting line and 5 seconds have elap

Mkey [24]

Bill's speed is constant after 5 seconds and 45 meters into the race.

Correct responses:

a. Bill's maximum speed is 8 m/s

b. 24 meters

c. 57 meters

<h3>Methods used to calculate speed and distance traveled</h3>

Given parameters are;

The distance of the race = 100 meter

Distance at which Bill reaches maximum speed = 45 meters

Speed Bill maintains after 5 seconds = The maximum speed

Time at which Bill is 85 meters from the starting line = 10 seconds after start

a. Required;

Bill's maximum speed in meters.

Solution:

Distance Bill runs at maximum speed, d = 85 m - 45 m = 40 m

Time at which Bill runs the 40 m at maximum speed, t = 10 s - 5 s = 5 s

$Speed = \mathbf{\dfrac{Distance}{Time}}$

Therefore;

$Bill's \ maximum \ speed = \dfrac{40 \ m}{5 \ s} = \underline{8 \ m/s}$

b. i. Required:

The distance Bill will run for 3 seconds at the maximum speed;

Solution:

Distance, s = Speed, v × Time, t

The distance traveled at maximum speed in 3 seconds is therefore;

Distance = 8 m/s × 3 s = 24 m

The distance Bill travels in 3 seconds at the maximum speed is 24 meters.

ii) The distance Bill travels at 8 seconds after start, is given as follows;

Distance traveled in the first 5 seconds = 45 meters

Distance traveled in the next 3 seconds = 24 meters

Therefore;

Bill's distance from the starting line 8 seconds after start is 45 meters + 25 meters = 69 meters

c. Bill's distance 6.5 seconds after the start of the race is given as follows;

Distance traveled in the first 5 seconds = 45 meters

Distance traveled in the next 1.5 seconds = 1.5 s × 8 m/s = 12 meters

Bill's distance from the starting line 6.5 seconds after start of the race = 45 meters + 12 meters = 57 meters

Learn more about distance, speed, time, relationship here:

https://brainly.in/question/49075584

6 0

2 years ago

A cylinder has a volume of 198 and base has an area of 22 what is the height o the cylinder

Mumz [18]

Answer:

Step-by-step explanation:

The base of the cylinder is in the shape of a circle:

Area of the base= $\pi *r^2$

For Base area=22 square units

$22=\pi *r^2$

$22=3.14*r^2\\r^2=22/3.14\\r^2=7.01\\r=\sqrt{7.01}$

Volume of the cylinder= $\pi *r^2*h$

For volume '198 cubic units' the height(h) is:

$198=\pi *r^2*h$

$198=3.14*(\sqrt{7.01})^2*h$

$198=3.14*7.01*h\\\\198=22.01*h\\\\198/22.01=h\\\\h=9 units\\$

4 0

3 years ago