Question

one positive integer is 7 less than another. The product of two integers is 44. what are the integers?

Answer 1

Answer:

4 and 11

Step-by-step explanation:

Lets call the smallest n

And the other one n+7

Then,

n.(n+7)=44

n²+7n=44

Subtract 44 from both sides.

n²+7n-44=44-44

n²+7n-44=0

Factorize the equation.

n²+11n-4n-44=0

n(n+11)-4(n+11)=0

(n+11)(n-4)=0

n+11=0 , n-4=0

n=-11 , n=4

n=4 is the only positive solution, so the numbers are:

4 and 11....

Answer 2

Answer:

The two integers are: 4 and 11.

Step-by-step explanation:

We are given that one positive integer is 7 less than another. Given that the product of two integers is 44, we are to find the integers.

Assuming $x$ to be one positive integer and $y$ to be the other, we can write it as:

$x=y-7$ --- (1)

$x.y=44$ --- (2)

Substituting x from (1) in (2):

$(y-7).y=44$

$y^2-7y-44=0\\\\y^2-11y+4y-44=0\\\\y(y-11)+4(y-11)$

y = 11

Substituting y = 11 in (1) to find x:

$x=11-7$

x = 4