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Marysya12 [62]
3 years ago
8

The figure below shows a line graph and two shaded triangles that are similar: A line is shown on a coordinate grid. The x-axis

values are from negative 15 to positive 15 in increments of 3 for each grid line. The y-axis values are from negative 5 to positive 5 in increments of 1 for each grid line. The line passes through the ordered pairs negative 12, 4, and 0, 0, and 12, negative 4. A shaded right triangle is formed so that its hypotenuse is from ordered pair 0, 0 labeled as O to 6, negative 2 labeled as A, one leg is from 0, 0 to 0, negative 2, and the second leg is from 0, negative 2 to 6, negative 2. Another shaded right triangle is formed with the hypotenuse from 6, negative 2 to 9, negative 3 labeled as B, one leg is from 6, negative 2 to 6, negative 3, and the second leg is from 6, negative 3 to 9, negative 3. Which statement about the slope of the line is true?
A. It is fraction negative 1 over 3 throughout the line.
B. .It is −3 throughout the line.
C. The slope from point O to point A is fraction 1 over 3 times the slope of the line from point A to point B.
D. The slope from point O to point A is three times the slope of the line from point A to point B.
Mathematics
1 answer:
german3 years ago
6 0

Answer:

D -  The slope from point O to point A is three times the slope of the line from point A to point B.

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Samantha opened a savings account and deposited $200.00. The account earns 10% interest, compounded monthly. If she wants to use
noname [10]

Answer:

200(1.10^1)

Step-by-step explanation:

6 0
3 years ago
Suppose a and b are both non zero real numbers. Find real numbers c and d such that 1/a+ib= c+id
Thepotemich [5.8K]

\begin{gathered} c=\frac{a}{a^2+b^2} \\ d=\frac{-b}{a^2+b^2} \end{gathered}

Explanation

\frac{1}{a+bi}=c+di

Step 1

multiplicate by the conjugate

\begin{gathered} \frac{1}{a+bi}\cdot\frac{a-bi}{a+bi}=\frac{a-bi}{(a+bi)(a-bi)}=\frac{a-bi}{a^2-(bi)^2} \\ \frac{1}{a+bi}\cdot\frac{a-bi}{a+bi}=\frac{a-bi}{(a+bi)(a-bi)}=\frac{a-bi}{a^2-(-b^2)}=\frac{a-bi}{a^2+b^2} \end{gathered}

notice that

\begin{gathered} \frac{1}{a+bi}=\frac{a-bi}{a^2+b^2}=\frac{a}{a^2+b^2}-\frac{b}{a^2+b^2}i \\ \frac{a}{a^2+b^2}-\frac{b}{a^2+b^2}i=c+di \\ so \\  \end{gathered}\begin{gathered} c=\frac{a}{a^2+b^2} \\ d=\frac{-b}{a^2+b^2} \end{gathered}

I hope this helsp you

6 0
1 year ago
Please help and write the steps to fine the answer (ignore the erasings)
podryga [215]

Answer: 1/50

Step-by-step explanation:

= 2 * 10^-2 * 2^0

= 2 * 1/10^2 * 1 (2^0=1)

= 2/100

= 1/50

3 0
3 years ago
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4x^2-25=39<br> Solve for x
pashok25 [27]

Answer:

u can find the answer in calculate

8 0
3 years ago
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The perimeter of a rectangular field is 320320 yd. the length is 2020 yd longer than the width. find the dimensions.
hichkok12 [17]
The sum of length and width is half the perimeter, 160 yd. The length is the average of the sum and difference of dimensions:
.. (160 +20)/2 = 90
Then the width is 160 -90 = 70

The rectangular field is 70 yd by 90 yd.
6 0
3 years ago
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