Answer: 3080/5280 or (simplified) 7/12
Explanation:
There are 5280 feet in one mile so 3080/5280 is equal to 3080 ft/ 1 mile.
7/12 is equal to 3080/5280 when simplified.
x = -38/9 !!!
27(x+4)=−6
Step 1: Simplify both sides of the equation.
27(x+4)=−6
(27)(x)+(27)(4)=−6 (Distribute)
27x+108=−6
Step 2: Subtract 108 from both sides.
27x+108−108=−6−108
27x=−114
Step 3: Divide both sides by 27.
27x/27=−114/27
x=−389
Answer:
x = 10, y = 12
Step-by-step explanation:
There is a 2:1 ratio between 16 and 8, alternate side lengths.
2x = 20
x = 10
2(6) = y
y = 12
Answers:
1. 1/4
2. 12:10
3. 3/23 in fraction form, or 0.13 in decimal form (though please note that the decimal form has been rounded to the nearest hundredth).
Explanations:
1. In order to simplify a fraction, you need to find a number that both the numerator and denominator can be divided by evenly. Once you cannot find any number that fits that description, you have found the simplest form. Both numbers 10 and 40 can be divided by the number 10 - so let's divide 10 by 10 and 40 by 10. After doing that, your answer should be 1/4.
2. In order to find an equivalent ratio of an existing ratio, you can just multiply or divide the numbers of that ratio by a same number. Knowing this, this question can have many correct answers, but in this case, I used the number 2, and multiplied both 6 and 5 by it. This left me with an equivalent ratio of 12:10.
3. In order to calculate probability, you need to divide the number of "winners" (or the outcome we want to have) by the number of all possible outcomes you could have. For this problem, that "winner" is the number of green shirts, which is 3. The number of outcomes would be the number of all the shirts in total, which adds up to 23. Thus, using that method explained earlier, the probability would be 3/23 in fraction form or 0.13 in decimal form (note that this is rounded to the nearest hundredth since dividing 3 by 23 would result in a long answer).
They are both similar.
tri cba ~ tri rqp
AA theorem
tri bac ~ tri edf
SSS theorem