The solution to the problem is as follows:
x = log (25) (125)
125 = 25^x
log 125 = x log 25
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x = 3/2
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11. You’ve done it correctly
12. Let x^2=y
y^2+13y+40=0
(y+8)(y+5)=0
y=8, 5
Since y=x^2
x^2=8 x^2=5
x=+/-√5 x= +/-2√2
13. x^4-x^2-x^2-8=0
x^4-2x^2-8=0
let x^2=y
Y^2-2y-8=0
(y-4)(y+2)=0
y=4, -2
Since y=x^2
X^2=4 X^2=-2
X= +/- 2 This wouldn’t be a real solution
14. It’s pretty much the same process, just substitute y in for x^2. If you’re confused feel free to ask and I can do it, or you can put it through Photomath
15. You’re on the right track so I’m just going to continue from where you left off
x^2(4x+5)-4(x+5)=0
(x^2-4)(4x+5)=0
x= +/- 2 4x=5
x=5/4 or 1 1/4
Hope this helped :)
Answer:
1,05
Step-by-step explanation:
Answer:
64°
Step-by-step explanation:
∠RQP = 46°
∠PRQ = 180° - 110° = 70°
∠PRQ + ∠RQP + <u>∠RPQ</u> = 180°
70° + 46 + <u>∠RPQ</u> = 180°
116° + <u>∠RPQ</u> = 180°
Find <u>∠RPQ</u>
<u>∠RPQ</u> = 180° - 116° = 64°
2(4x + 3y). You just factor out the two
