Answer:
yes, the student who has 8 pets.
Step-by-step explanation:
the majority of the class has between 0-4 pets leaving the student with 8 to be the "outlier"
Answer:
a. 1.2 ohms
b. 6 ohms
Step-by-step explanation:
As with any problem involving evaluation of a formula, substitute the given values for the corresponding variables and do the arithmetic.
a.

__
b.

_____
<em>Comment on these problems</em>
You will notice that the values in part (b) are 5 times those in part (a). So, it is no surprise that the answer in part (b) is 5 times the answer in part (a).
Answer:
The answer is 3030.72 m³
Step-by-step explanation:
Please refer to attached file for graphical representation.
Formulas used:
Area = (a*b)/2
Trigonometry: Tan (t) = opposite/adjacent
Assume:
Villager plot has 3 sides: hypotenuse=C, adjacent=A, opposite=B
Plot given has 3 sides: hypotenuse=z, adjacent=y, opposite=x
Angle common between them is t.
<u>Step 1</u>:
For t:
Tan (t) = a/b
Tan (t) = 123/50
Tan (t) = 2.46
<u>Step 2:</u>
For y:
Tan (t) = y/x
2.46 = y/6
y = 2.46*6
y = 14.76
<u>Step 3:</u>
Villagers old plot area: B = (a*b)/2 = (123*50)/2
B = 3075 m³
<u>Step 4:</u>
Plot donated area: C = (x*y)/2 = (6*14.76)/2
C = 44.28 m³
<u>Step 5:</u>
Villager remaining plot:
A = B-C
A= 3075-44.28
A = 3030.72 m³
Your answer is (1,7) hopes this helps