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Bond [772]
3 years ago
13

The quotient of two rational numbers is positive. What can you conclude about the signs of the dividend and the divisor?

Mathematics
2 answers:
Nikitich [7]3 years ago
7 0

1) both  have  positives    signs    OR

2) both  have    negatives signs

Pavel [41]3 years ago
5 0

Answer:

Knowing that the quotient of two rational numbers is positive, leads me to the conclusion that both the dividend and the divisor were the same. When I say the same, I mean they were either both positive or both negative.

I hope this helps

Please mark me the brainliest.

    - Madison Croskey

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kherson [118]

Answer:

a. The alternative hypothesis H₀: p'₁ ≠ p'₂ is accepted

b. Type I error

Step-by-step explanation:

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p'₁ = 0.08 * 11545 =923.6

p'₂ = 0.088 * 4691=412.81

σ₁ = \sqrt{n*p_1*q_1}  = \sqrt{n*p_1*(1-p_1)} = \sqrt{11545*0.08*(1-0.08)} = 29.15

σ₂ = \sqrt{n*p_2*q_2}  = \sqrt{n*p_2*(1-p_2)}= \sqrt{4691*0.088*(1-0.088)} = 19.40

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Samples size of Oregon residents n₂ = 4,691

Hypothesis can be constructed thus

Let our null hypothesis be H ₀: p'₁ = p'₂

and alternative hypothesis H ₐ: p'₁ ≠ p'₂

Then we have  

z =\frac{(p'_1 -p'_2)-(\mu_1-\mu_2)}{\sqrt{\frac{\sigma^2_1}{n_1}+\frac{\sigma^2_2}{n_2} } }

The test statistics can be computed by

     

t₀ = \sqrt{\frac{n_1n_2(n_1+n_2-2)}{n_1+n_2} } *\frac{p_1'-p_2'}{\sqrt{(n_1-1)\sigma_1^2+(n_2-1)\sigma_2^2} } =      1104.83

c from tables is   P(T ≤ c) = 1 - α where α = 5% and c = 1.65

since t₀ ≥ c then then the hypothesis is rejected which means the alternative hypothesis is rejected

b. Type I error, rejecting a true hypothesis

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3 years ago
PLEASE HELP
vampirchik [111]

Answer:

b

Step-by-step explanation:

Because when you add up the points you would get (4,3)

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