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m_a_m_a [10]
3 years ago
9

Help needed please! *will mark as brainliest if correct

Mathematics
1 answer:
Svet_ta [14]3 years ago
6 0
2 gophers per day are getting removed
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Module Six Project Option 1
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If each letter of the alphabet is worth two more than its preceding letter, where A is the first number and equals 1, B is the s
andrey2020 [161]

Answer:

<h2>The total value of all the letters in the alphabet is 676.</h2>

Step-by-step explanation:

The problem is about an arithmetic sequence where the difference is 2, the first term is 1 and we know that the alphabet has 26 letters.

To find the total sum of all values, we have to use the following formula

S_{n}=\frac{n}{2}(2a_{1}+(n-1)d )

Where n=26, a_{1}=1 and d=2. Replacing values, we have

S_{26}=\frac{26}{2}(2(1)+(26-1)2) =13(2+50)=13(52)=676

Therefore, the total value of all the letters in the alphabet is 676.

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3 years ago
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Step-by-step explanation:

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Step-by-step explanation:

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Simplify 5(x - 6).<br> 5x - 6<br> 0 5x - 30
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Answer:

It depends on what property you use

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If you use the distributive property then you would get 5x-30

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