Answer:
- 11040 m³
- k ≈ 0.33
- V = (1/3)Bh
Step-by-step explanation:
The given relation is ...
V = kBh . . . . . for some base area B, height h, and constant of variation k
We are given length and width of the base so we presume it is a rectangle.
B = l·w = 8·11 = 88 . . . . square meters
The given volume tells us the value of k:
1144 = k(88)(39) . . . . . . cubic meters
1144/3432 = k = 1/3 ≈ 0.33
The value of k is about 0.33.
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Then the volume of the larger pyramid is ...
V = (1/3)(15 m)(46 m)(48 m) = 11,040 m³
The general relationship is ...
V = 1/3Bh
Just round 25.99 to 26 and divide it by two. This gives you 13, which is less than 14.. You would be able to buy the video game.
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Step-by-step explanation:
The solutions are 2 and 5
Because it's asking what would make the triangles congruent, you would set up the equation like this because the angles (angle 3 and angle 4) need to be equal:
x^2 = 7x - 10
Next, you add 10 to both sides. This is so that you can move it to the other side, addition is the inverse of subtraction.
x^2 + 10 = 7x
Now subtract 7x from both sides. Subtraction is the inverse of addition. You do this to get it on the other side so you can factor it. You can move the 10 and 7x to the other side in any order or at the same time, I just did it like this.
x^2 - 7x + 10 = 0
Now, factor. I don't really know how to explain factoring, you just get a feel for it with a lot of practice.
(x - 2)(x - 5) = 0
You can use FOIL to check this if you want to. x(x) is x^2, -2(-5) is 10), -2x - -5x is -7x. Now, find what you need to do to make what's in each of the groups of parentheses equal to 0.
x - 2 = 0
x = 2
One of the solutions is 2, because you add 2 to x to get 0.
x - 5 = 0
x = 5
The other solution is 5, because you add 5 to x to get 0. Lastly, check your solutions by plugging them in to the original equation.
2^2 = 7(2) - 10
4 = 14 - 10
So 2 is definitely a solution.
5^2 = 7(5) - 10
25 = 35 - 10
5 is also a solution.
Hope that helps :]
<h3>
Answer: C) increase from 45 degrees to 50 degrees</h3>
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Explanation:
Let's calculate the angle B based off the arcs CDF and GHJ
B = (far arc - near arc)/2
B = (arc CDF - arc GHJ)/2
B = (130 - 40)/2
B = 90/2
B = 45
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Now let's change GHJ to 30 degrees, while keeping the other arc the same.
B = (far arc - near arc)/2
B = (arc CDF - arc GHJ)/2
B = (130 - 30)/2
B = 100/2
B = 50
Angle B has increased from 45 degrees to 50 degrees.
