For this case, we perform the conversions:
First roll:
We make a rule of three to determine the number of "c" boxes that can be packed with 300 meters of adhesive tape.
1 -----------> 4.2
c -----------> 300
You can pack 71 boxes.
Second roll:
We make a rule of three to determine the number of "c" boxes that can be packed with 70 meters of adhesive tape.
1 -----------> 4.2
c -----------> 70
You can pack 16 boxes.
Third roll:
1 -----------> 4.2
c -----------> 50
You can pack 11 boxes.
Thus, in total you can pack
Answer:
98 boxes
Answer:
16 rides
Step-by-step explanation:
Option 1 . Admission fee = $10
Each ride = $0.50
Option 2 . Admission fee = $6
Each ride = $0.75
Let no. of rides be x
So, cost of ride according to option 1 = 0.50x
So, total cost after having x rides according to option 1 :
= 10+0.50x ---1
Cost of ride according to option 2 = 0.75x
So, total cost after having x rides according to option 2 :
= 6+0.75x --2
Now to find the beak even point i.e. having the same cost
Equate 1 and 2
Thus for 16 rides , the two options have the same cost .
Hence the break even point is 16 rides
Methods for solving a system of equations:
- elimination
- substitution
- augmented matrix
Ranks of method ( number one being the most preferred method)
1) elimination
2) substitution
3) augmented matrix
Elimination is my preferred method because it is simple and easy to work out and hard to get wrong.
Augmented matrix is my least preferred method because it is easy to get wrong and it requires complex steps to solve a simple equation.
Hope this helps ;)
There vetocity is D/t =s is ükùû
Answer:
10.5 square units
Step-by-step explanation:
