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3 years ago

Ce What is the distance between (-4,-10) and (-4, -4)? o 3 units 04 units 06 units 08 units

Mathematics

1 answer:

ANTONII [103]3 years ago

6 0

Answer:

06 units

Step-by-step explanation:

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Pls help and show workings <br> Due ASAP

tester [92]

Answer: B

Step-by-step explanation:

The equation $y+2=\frac{3}{4} x-8$ is not yet in slope-intercept form( $y=mx+b$ ). Simply subtract 2 from both sides to turn the equation into slope intercept form as $y=\frac{3}{4}x-10$ . For a line to be perpendicular to another, it must have an opposite reciprocal slope. A reciprocal is the fraction reversed, where the numerator is the denominator and vice versa. Thus, 3/4 would become 4/3. The opposite reciprocal of 3/4 would be -4/3.

The slope of the line given is 3/4. Thus, simply plug in the opposite reciprocal of 3/4 for the slope to get: $y=-\frac{4}{3} x+b$ . Then, because the line passes through -12, 1, plug those values in for x and y, respectively.

$1=-\frac{4}{3}*-12+b$

$1=16+b$

$-15=b$

Thus, the equation of the line is $y=-\frac{4}{3} x-15$ , or B.

Hope it helps :D

4 0

3 years ago

A cable company must provide service for 6 houses in a particular neighborhood. They would like to wire the neighborhood in a wa

8_murik_8 [283]

Answer:

1650 yards

Step-by-step explanation:

Here, we have to find the minimal spanning tree required to span the neighborhood.

We start from house 1. The minimum distance from house 1 to house 2 is 250 yards. Now from 2, we can go to house 3,4 or 5 all having the equal distances of 400 yard from house 2. So we go to from house 2 to house 3. Now from 3, we go to house 5 which is at a minimum distance of 350 yards. Now from house 5 we go to house 4 with 300 yards and then from house 4 we go to house 6 which is at 350 yards from 4.

Thus the network is complete and the total distance covered is

= 250 + 400 + 350 + 300 + 350

= 1650 yards

This is the minimum distance by which the neighborhood can be wired.

And the tree is

$1\rightarrow2\rightarrow3\rightarrow5\rightarrow4\rightarrow6$

4 0

3 years ago

Consider these four data sets. Set A: {32, 12, 24, 46, 18, 22, 14} Set B: {4, 12, 11, 14, 11, 5, 12, 13, 18, 14} Set C: {5, 4, 9

drek231 [11]

SET A

The elements of this set are,

$32,12,24,46,18,22,24$

We arrange this data set in ascending order to get,

$12,18,22,24,24,32,46$

The median for this data set is

$median = 24$

The mean for this data set can be calculated using the formula,

$\bar X = \frac{ \sum x}{n}$

This implies that,

$\bar X = \frac{ 12 + 18 + 22 + 24 + 24 + 32 + 46}{7}$

$\bar X = \frac{154}{7} = 22$
This data set is negatively skewed because the mean is less than the median.

SET B

This set contains the elements,

$4, 12, 11, 14, 11, 5, 12, 13, 18, 14$

We arrange the elements of this set in ascending order to obtain,

$4,5,11,11,12,12,13,14,14,18$

The median for this data set is,

$median = \frac{12 + 12}{2} = 12$

The mean is

$\bar X = \frac{4 + 5 + 11 + 11 + 12 + 12 + 13 + 14 + 14 + 18}{10}$

.
$\bar X = \frac{114}{10} = 11.4$

This data set is negatively skewed because the mean I'd less than the median.

SET C

The set C has elements,
$5, 4, 9, 12, 14, 26, 22, 18$

We arrange this set in ascending order to get,

$4,5,9,12,14,18,22,26$

The median of this data set is

$median = \frac{12 + 14}{2} = 13$

The mean of this data set is
$\bar X = \frac{4 + 5 + 9 + 12 + 14 + 18 + 22 + 26}{8}$

$\bar X = \frac{110}{8} = 13.75$

This is a positively skewed distribution because the mean is greater than the median

SET D

The elements of this set are

$1, 1, 1, 2, 2, 3, 3, 4, 5, 6$

The median of this data set is

$median = \frac{2 + 3}{2} = 2.5$

The mean is
$\bar X= \frac{1 + 1 + 1 + 2 + 2 + 3 + 3 + 4+ 5 + 6}{10}$

$\bar X= \frac{28}{10} = 2.8$

This data set is positively skewed because the mean is greater than the median.

4 0

3 years ago

Read 2 more answers

An air traffic controller spots two airplanes at the same altitude converging to a point as they fly at right angles to each oth

muminat

So.... notice the picture below

we know when y = 140 and x = 240, r = 250

so let's use the pythagorean theorem

$\bf r^2=x^2+y^2\implies 2r\cfrac{dr}{dt}=2x\cfrac{dx}{dt}+2y\cfrac{dy}{dt}\implies \cfrac{dr}{dt}=\cfrac{x\frac{dx}{dt}+y\frac{dy}{dt}}{r}
\\\\\\
\cfrac{dr}{dt}=\cfrac{240\cdot 480+70\cdot 140}{250}\implies \cfrac{dr}{dt}=500$

now... how much time does the controller have? well, say, plane "y" is going at dy/dt of 140mph, and is 70 miles away, 140 is 2*70, so it can cover those 70 miles in 1/2 hr, and when it does, it'll collide with the other,

so, the controller has that much, less than 1/2 hr

8 0

4 years ago

Given the function f(x) = 4(x + 1)^2 – 3, indicate the shifts that will affect the location of the vertex, and explain what effe

solniwko [45]

He first two are relatively easy. f(x-2) shifts it sideways (2 to the right in this case) f(x) -2 shifts it straight down (by 2)
f(2x) means replace x with 2x in the original 4(2x + 1)^2 − 3 if you factor out the 2 from the square root you get 4*sqr(2) ( x + ½)^2 - 3 which is now in the form a ( x -h)^2 + k the vertex is now at (-½, -3) (it used to be at (-1,-3) the "a" has gotten bigger, which makes the parabola "skinnier" (it goes up faster)
2•f(x) becomes 2*( 4(x + 1)2 − 3 ) = 8 (x+1)^2 -6 where is the vertex now? is this parabola fatter or skinnier than the original f(x) ?

8 0

4 years ago

Ce What is the distance between (-4,-10) and (-4, -4)? o 3 units 04 units 06 units 08 units​

Ce What is the distance between (-4,-10) and (-4, -4)? o 3 units 04 units 06 units 08 units