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Svetllana [295]
3 years ago
13

Which of the following is equivalent to -7/-12? 7/-12 7/12 12/7

Mathematics
2 answers:
kolbaska11 [484]3 years ago
5 0

Step-by-step explanation:

7/ 12 is equivalent to - 7/-12

Zina [86]3 years ago
5 0
7/12 is equivalent to -7/-12
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Can someone smart help me here?
V125BC [204]
The answer is 573

S is the three digit number.
h - a number of hundreds
t - a number of tens
o - a number of ones

S = 100h + 10t + o

<span>The last two digits add to make ten: t + o = 10
</span><span>The first and last digits add to make eight: h + o = 8
</span><span>The first two digits add to make twelve: h + t = 12

</span>t + o = 10          ⇒ o = 10 - t
h + o = 8           ⇒ o = 8 - h
_______
10 - t = 8 - h
h + t = 12          ⇒ h = 12 - t
_______
10 - t = 8 - (12 - t)
10 - t = 8 - 12 + t
10 - t = -4 + t
10 + 4 = t + t
2t = 14
t = 14/2 = 7
______

h = 12 - t = 12 - 7 = 5
______

o = 8 - h = 8 - 5 = 3

S =  100h + 10t + o
h = 5
t = 7
o = 3

S = 100*5 + 10*7 + 3
   = 500 + 70 + 3
   = 573
8 0
3 years ago
Kate begins solving the equation (6x – 3) = (6x – 4). Her work is correct and is shown below. (6x – 3) = (6x – 4) 4x – 2 = 3x –
Alexxandr [17]

Answer:

x = 0.

Step-by-step explanation:

4x = 3x

4x - 3x = 0

x = 0

Hope this helps!

3 0
3 years ago
Quick QUICK QUICK QUICK PLEASEEEEEEEE! 1 MINUTE ONLY 30 POINTS WILL BE BRAINLIEST!
mihalych1998 [28]
Theatre A uses 2.5 cups of salt
5 0
2 years ago
Read 2 more answers
Factor x^3−5x^2−25x+125
UkoKoshka [18]
(x-5)^2 . ( x+5)
=( x^2 - 10x + 25) . ( x+ 5)
=x^3 + 5x^2 - 10x^2 -50x + 25x + 125
= x^3 - 5x^2 -25x +125
5 0
3 years ago
Determine whether the following series converges or diverges using the integral test. Be sure to verify that the integral test c
Finger [1]

By using the integral test, series converges

What is an integral test for convergence and divergence?

⇒ It is used to prove the divergence or convergence of series. This test is called the integral test, which compares an infinite sum to an improper integral. It is important to note that this test can only be applied when we are considering a series whose terms are all positive.

How to know if a series is converging or diverging?

If the limit exists and is a finite number (a number less than infinity), we say the integral converges. If the limit is ±∞ or does not exist, we say the integral diverges.

let aₓ= f (x) is any function

⇒ In order for the integral test to work The function must be positive it has to be continuous and it has to be decreasing when x≥1

If the integral converges it means the series is also converging

If the integral diverges it means the series is also diverging

The sequence k^{3} /{e^{k^{4} } is clearly positive and decreases for k∈N then by the integral test,

\int\limits^\infty_1 {x^{3} /e^{x^4} dx \leq\displaystyle \sum^{\infty}_{k = 1} {x^{3} /e^{x^{4}

and

\int\limits^\infty_1 {x^{3} /e^{x^4} dx=1/4\int\limits^\infty_1 {x^{3} /e^{-u} du

⇒ 1/4 < \infty

So it comes with a finite value hence the series converges

Learn more about the integral tests here :

brainly.com/question/15394015

#SPJ1

4 0
1 year ago
Read 2 more answers
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