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loris [4]
3 years ago
13

If x varies jointly as y and z , and x =8 when y = 4 and z=9, find z when x =16 and y =6

Mathematics
2 answers:
Likurg_2 [28]3 years ago
7 0
X = 8 when y = 4 and z = 9, then k = x/(yz) = 8/(4*9) = 2/9. The equation is x = (2/9)yz. when x = 16 and y = 6, (2/9)*6*z = 16, solve the equation we get z = 12
GenaCL600 [577]3 years ago
5 0

Answer: Hello mate!

Joint variation means that x varies with the product of z and y, then we can write this as:

x = k *(yz) where k is a real number.

we know that x is 8 when y = 4 and = 9, and with this information, we could obtain the value of k.

8 = k*(4*9) = k*(36)

then k = 8/36 = 2/9

now, if x = 16 and y = 6, we need to find the value of z, we replace the values of x and y in our equation and isolate z:

16 = (2/9)*(6z)

16 = (12/9)z

16*(9/12) = z = 12

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Find the exponential function that passes through the points (2,80) and (5,5120)​
juin [17]

Answer:

  y = 5·4^x

Step-by-step explanation:

If you have two points, (x1, y1) and (x2, y2), whose relationship can be described by the exponential function ...

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you can find the values of 'a' and 'b' as follows.

Substitute the given points:

  y1 = a·b^(x1)

  y2 = a·b^(x1)

Divide the second equation by the first:

  y2/y1 = ((ab^(x2))/(ab^(x1)) = b^(x2 -x1)

Take the inverse power (root):

  (y2/y1)^(1/(x2 -x1) = b

Use this value of 'b' to find 'a'. Here, we have solved the first equation for 'a'.

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In summary:

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For the problem at hand, (x1, y1) = (2, 80) and (x2, y2) = (5, 5120).

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3 years ago
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FREE BRAINLIEST!: (n+2) to the power of 2 - 5a + 1 when n=6 and a=2
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