P= 4(348) because assuming the wear house has four sides that is the only logical answer
answer:X=k/n-3
explain:move all terms to the left side and set equal to zero. then set each factor equ to zero!
I hope this helps
There are 10 balls in the Urn Total.
Red: 6
Green: 4
Question One: The probability that five red and two green is selected is likely. (as that is over half for both)
Question Two: Impossible. There is only 6 red balls, and 7 are taken from the urn. Thus it would at most be possible for 6 red and 1 green.
Question Three: At least four is likely, as there is more red then green in the Urn.
Hope I helped!
(Mark Brainliest if you can please!)
You can use desmos! and to solve you find the point(s) where they overlap
