5x3-4x2-20x+16=0 Three solutions were found : x = 4/5 = 0.800 x = 2 x = -2Reformatting the input :Changes made to your input should not affect the solution:
(1): "x2" was replaced by "x^2". 1 more similar replacement(s).
Step by step solution :Step 1 :Equation at the end of step 1 : (((5 • (x3)) - 22x2) - 20x) + 16 = 0 Step 2 :Equation at the end of step 2 : ((5x3 - 22x2) - 20x) + 16 = 0 Step 3 :Checking for a perfect cube : 3.1 5x3-4x2-20x+16 is not a perfect cube
Trying to factor by pulling out : 3.2 Factoring: 5x3-4x2-20x+16
Thoughtfully split the expression at hand into groups, each group having two terms :
Group 1: 5x3+16 Group 2: -4x2-20x
Pull out from each group separately :
Group 1: (5x3+16) • (1)Group 2: (x+5) • (-4x)
I hope it helps
Answer:
1) as-16a
taknig a as common
=a(s-16)
2)as-4a³
taking a as common
=a(s-4a²)
3)2a³+8a-4a²-16
taking common terms
=2a(a²+4)-4(a²+4)
=(2a-4)(a²+4)
again taking common
=2(a-2)(a²+4)
i hope this will help you :)
Answer:
the answer is f(x) = 6x + 1/6
Step-by-step explanation:
the g(x) ones y intercept is : 0,-6
the -6k(x) ones y intercept is : 0 , -6
the f ( x) ones y inetrcept is ; 0 , 1/6
the h (x) ones y intercept is : 0 , 6
Answer: C
.Step-by-step explanation:
it was right for me so if its wrong im sorry :)
