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2 years ago

I need b and c ASAP pls

Mathematics

1 answer:

skelet666 [1.2K]2 years ago

7 0

Answer:

the photo is blocked

Step-by-step explanation:

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What is the general form of the equation of a circle with its center at (-2, 1) and passing through (-4, 1)?

AnnZ [28]

Answer:

$x^{2}+y^{2} +4x-2y+1=0$

Step-by-step explanation:

we know that

The general form of the equation of a circle is

$x^{2} +y^{2}+ Dx + Ey + F=0$

where D, E, F are constants

step 1

Find the radius of the circle

Remember that the distance from the center to any point on the circle is equal to the radius

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

$(-2,1)\\(-4,1)$

substitute the values

$r=\sqrt{(1-1)^{2}+(-4+2)^{2}}$

$r=\sqrt{(0)^{2}+(-2)^{2}}$

$r=2\ units$

step 2

Find the equation of the circle in standard form

$(x-h)^{2} +(y-k)^{2}=r^{2}$

In this problem we have

center ( -2,1)

radius r=2 units

substitute

$(x+2)^{2} +(y-1)^{2}=2^{2}$

$(x+2)^{2} +(y-1)^{2}=4$

Step 3

Convert to general form

$(x+2)^{2} +(y-1)^{2}=4\\ \\x^{2}+4x+4+y^{2}-2y+1=4\\ \\x^{2}+y^{2} +4x-2y+1=0$

7 0

3 years ago

Find the equation of the axis of symmetry of the graph of y = (x + 3)^2 - 5

Temka [501]

Equation of the parabola: y = ax^2 + bx + c. Find a, b, and c.
x of axis of symmetry:
x
=
−
b
2
a
=
3
-> b = -6a
Writing that the graph passing at point (1, 0) and point (4, -3):
(1) 0 = a + b + c -> c = - a - b = - a + 6a = 5a
(2) -3 = 16a + 4b + c --> -3 = 16a - 24a + 5a = -3a --> a = 1
b = -6a = -6; and c = 5a = 5
y
=
x
2
−
6
x
+
5

Check with x = 1: -> y = 1 - 6 + 5 = 0. OK

3 0

3 years ago

David created two functions. Function A can be represented by y=3/4x +2. Function be is represented by the graph below.

RideAnS [48]

Answer: don't know sorry

Step-by-step explanation:

7 0

2 years ago

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Here is an isosceles triangle.

harina [27]

Answer: